Ignore specific field on serialization with Jackson

Question

I'm using the Jackson library.

I want to ignore a specific field when serializing/deserializing, so for example:

public static class Foo {
    public String foo = "a";
    public String bar = "b";

    @JsonIgnore
    public String foobar = "c";
}

Should give me:

{
foo: "a",
bar: "b",
}

But I'm getting:

{
foo: "a",
bar: "b",
foobar: "c"
}

I'm serializing the object with this code:

ObjectMapper mapper = new ObjectMapper();
String out = mapper.writeValueAsString(new Foo());

The real type of the field on my class is an instance of the Log4J Logger class. What am I doing wrong?

score 91 · Accepted Answer · edited May 23 '17 at 12:03

Ok, so for some reason I missed this answer.

The following code works as expected:

@JsonIgnoreProperties({"foobar"})
public static class Foo {
    public String foo = "a";
    public String bar = "b";

    public String foobar = "c";
}

//Test code
ObjectMapper mapper = new ObjectMapper();
Foo foo = new Foo();
foo.foobar = "foobar";
foo.foo = "Foo";
String out = mapper.writeValueAsString(foo);
Foo f = mapper.readValue(out, Foo.class);

score 1 · Answer 2 · edited May 23 '17 at 10:31

1

Also worth noting is this solution using DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES: https://stackoverflow.com/a/18850479/1256179

edited May 23 '17 at 10:31

Community

1
1

answered Dec 15 '15 at 17:38

rwblackburn

371
3
13

score 0 · Answer 3 · answered Aug 08 '18 at 19:00

Reference from How can I tell jackson to ignore a property for which I don't have control over the source code?

You can use Jackson Mixins. For example:

class YourClass {
  public int ignoreThis() { return 0; }    
}

With this Mixin

abstract class MixIn {
  @JsonIgnore abstract int ignoreThis(); // we don't need it!  
}

With this:

objectMapper.addMixIn(YourClass.class, MixIn.class);

Ignore specific field on serialization with Jackson

3 Answers3