Use Module which is in a statically-linked object (Fortran)

Question

Dear stackoverflow experts,

I want to create (with FORTRAN) a shared object file, lets say myso.so. In this .so I have one module file, modso.f, and one 'subroutine file', subso.f.

I also have a statically-linked object (in FORTRAN again), lets say mya.a with 3 subroutine files, and 2 module files, moda1.f and moda2.f.

At the linking of myso.so, I include the mya.a, and of course the modso.o, subso.o. In the modso.f and subso.f, I have the USE statement for using the moda1.f and moda2.f modules that are in mya.a.

What's my problem is: When I open (during runtime of main program) the myso.so library (using the command dlopen(myso.so, RTLD_LAZY)), I get this error returning from dlerror(): myso.so: undefined symbol: moda1_

So in other words, it seems that the .so library can't see the modules in the .a library. In compiling and linking phase I didn't get any errors/warnings.

I'm using pgi 10 fortran 90 compiler under Ubundu. The above example works fine in windows (where the .so are .dll and .a are .lib)

Thanks in advanced.

I think you may need to show some (minimal, but complete) code. I don't understand why the symbol `moda1` would be referenced, since it is the name of a module, right? — eriktous, Jan 06 '12 at 00:42
Yes, moda1 is the name of the module (and both the filename). OK, I will try to post some code, thanks for the answer. — helios21, Jan 06 '12 at 10:02

score 1 · Accepted Answer · edited May 23 '17 at 10:34

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It might be because of linking order:

g++: In what order should static and dynamic libraries be linked?

Linking phase is successfull because symbols are resolved when dynamic library is loaded, not linked.

edited May 23 '17 at 10:34

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answered Jan 05 '12 at 14:32

Nikolay Polivanov

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Should I check linking order when I build .a or .so library? Thank you for reading my post – helios21 Jan 05 '12 at 19:19

Use Module which is in a statically-linked object (Fortran)

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