After searching for this same functionality, I ended up writing my own PHP
script to act as a proxy. The trouble I kept running into is even when you get the RAW version/link from Github
and link to it in your own page, the header sent over was 'text/plain' and Chrome
was not executing my JavaScript
file from Github
. I also didn't like the other links posted for using third party services because of the obvious security/tampering issues possible.
So using this script, I can pass over the RAW link from Github
, have the script set the correct headers, and then output the file as if it were coming from my own server. This script can also be used with a secure application to pull in non-secure scripts without throwing SSL
errors warning of "Non-secure links used".
Linking:
<script src="proxy.php?link=https://raw.githubusercontent.com/UserName/repo/master/my_script.js"></script>
proxy.php
<?php
###################################################################################################################
#
# This script can take two URL variables
#
# "type"
# OPTIONAL
# STRING
# Sets the type of file that is output
#
# "link"
# REQUIRED
# STRING
# The link to grab and output through this proxy script
#
###################################################################################################################
# First we need to set the headers for the output file
# So check to see if the type is specified first and if so, then set according to what is being requested
if(isset($_GET['type']) && $_GET['type'] != ''){
switch($_GET['type']){
case 'css':
header('Content-Type: text/css');
break;
case 'js':
header('Content-Type: text/javascript');
break;
case 'json':
header('Content-Type: application/json');
break;
case 'rss':
header('Content-Type: application/rss+xml; charset=ISO-8859-1');
break;
case 'xml':
header('Content-Type: text/xml');
break;
default:
header('Content-Type: text/plain');
break;
}
# Otherwise, try and determine what file type should be output by the file extension from the link
}else{
# See if we can find a file type in the link specified and set the headers accordingly
# If css file extension is found, then set the headers to css format
if(strstr($_GET['link'], '.css') != FALSE){
header('Content-Type: text/css');
# If javascript file extension is found, then set the headers to javascript format
}elseif(strstr($_GET['link'], '.js') != FALSE){
header('Content-Type: text/javascript');
# If json file extension is found, then set the headers to json format
}elseif(strstr($_GET['link'], '.json') != FALSE){
header('Content-Type: application/json');
# If rss file extension is found, then set the headers to rss format
}elseif(strstr($_GET['link'], '.rss') != FALSE){
header('Content-Type: application/rss+xml; charset=ISO-8859-1');
# If css xml extension is found, then set the headers to xml format
}elseif(strstr($_GET['link'], '.xml') != FALSE){
header('Content-Type: text/xml');
# If we still haven't found a suitable file extension, then just set the headers to plain text format
}else{
header('Content-Type: text/plain');
}
}
# Now get the contents of our page we're wanting
$contents = file_get_contents($_GET['link']);
# And finally, spit everything out
echo $contents;
?>