By using these two lines of code:
cli ; stop all interrupts
hlt ; halt the cpu
you could halt a bootable program for x86 pc:
BITS 16
start:
mov ax, 07C0h ; Set up 4K stack space after this bootloader
add ax, 288 ; (4096 + 512) / 16 bytes per paragraph
mov ss, ax
mov sp, 4096
mov ax, 07C0h ; Set data segment to where we're loaded
mov ds, ax
cld ; clear direction flag
mov si, text_string ; Put string position into SI
call print_string ; Call our string-printing routine
cli ; stop all interrupts
hlt ; halt the cpu
jmp $ ; Jump here - infinite loop!
text_string db 'Hello World!', 0
print_string: ; Routine: output string in SI to screen
mov ah, 0Eh ; int 10h 'print char' function
.repeat:
lodsb ; Get character from string
cmp al, 0
je .done ; If char is zero, end of string
int 10h ; Otherwise, print it
jmp .repeat
.done:
ret
times 510-($-$$) db 0 ; Pad remainder of boot sector with 0s
dw 0xAA55 ; The standard PC boot signature
Save it as "prog.asm", then use "nasm" to create boot sector:
nasm -f bin -o boot.img prog.asm
Now you could use "qemu" to test it:
qemu-system-i386 -drive file=boot.img,index=0,media=disk,format=raw -boot c -net none
Note: Removing those two lines mentioned above, causes your virtual machine to use maximum cpu cycles available.
Edit: Added "cld" instruction. As mentioned by Michael, it was necessary to make sure text_string is loaded from left-to-right.