Regular expression for date format- dd-mm-yyyy in Javascript

Question

I need a regular expression for date format: dd-mm-yyyy in Javascript.

you can go [here](http://stackoverflow.com/questions/5465375/javascript-date-regex-dd-mm-yyyy) for previously answered question — cctan, Jan 20 '12 at 06:16

score 34 · Accepted Answer · answered Jan 20 '12 at 06:13

34


function parseDate(str) {
  var m = str.match(/^(\d{1,2})-(\d{1,2})-(\d{4})$/);
  return (m) ? new Date(m[3], m[2]-1, m[1]) : null;
}

answered Jan 20 '12 at 06:13

Sudhir Bastakoti

99,167
15
158
162

I needed similar which allows (4/6/17 , 04/6/2017, 4/06/17, 04/06/2017 , 04/06/17 etc) so I just changed it bit: /^(\d{1,2})\/(\d{1,2})\/(\d{2,4})$/ – Renascent Apr 20 '18 at 09:26

gdZeus · Answer 2 · 2018-10-23T19:03:16.103

15

Notice

Your regexp does not work for years that "are multiples of 4 and 100, but not of 400". Years that pass that test are not leap years. For example: 1900, 2100, 2200, 2300, 2500, etc. In other words, it puts all years with the format \d\d00 in the same class of leap years, which is incorrect. – MuchToLearn

So it works properly only for [1901 - 2099] (Whew)

dd-MM-yyyy

Checks if leap year. Years from 1900 to 9999 are valid. Only dd-MM-yyyy

var stringToValidate = "29-02-2012";
var rgexp = /(^(((0[1-9]|1[0-9]|2[0-8])[-](0[1-9]|1[012]))|((29|30|31)[-](0[13578]|1[02]))|((29|30)[-](0[4,6,9]|11)))[-](19|[2-9][0-9])\d\d$)|(^29[-]02[-](19|[2-9][0-9])(00|04|08|12|16|20|24|28|32|36|40|44|48|52|56|60|64|68|72|76|80|84|88|92|96)$)/;
var isValidDate = rgexp.test(stringToValidate);

edited Oct 23 '18 at 19:03

answered Dec 25 '13 at 13:53

gdZeus

1,081
8
7

Could you explain your regular expression..? – Gangadhar Jannu Oct 14 '14 at 06:23
@GangadharJannu Sorry for the delay in responding, I did not notice you question – gdZeus Jun 29 '15 at 14:58
`(0[1-9]|[12][0-8])[-](0[1-9]|1[012])` - days: from 1 to 28 for any months – gdZeus Jun 29 '15 at 15:18
`((29|30|31)[-](0[13578]|1[02]))` - days: 29, 30, 31 for months: 1, 3, 5, 7, 8, 10, 12 – gdZeus Jun 29 '15 at 15:18
`(29|30)[-](0[469]|11)` - days: 29, 30 for months: 4, 6, 9, 11 – gdZeus Jun 29 '15 at 15:19
`(00|04|08|12|16|20|24|28|32|36|40|44|48|52|56|60|64|68|72|76|80|84|88|92|96)$)` years that ends with 00, 04, 08, etc. are leap years – gdZeus Jun 29 '15 at 15:21
`(^29[-]02[-](19|[2-9][0-9])(00|04|08|12|16|20|24|28|32|36|40|44|48|52|56|60|64|68|72|76|80|84|88|92|96)$)` 29-02-only for leap years – gdZeus Jun 29 '15 at 15:21
No problem @gdZeus. Thanks for answering – Gangadhar Jannu Jul 01 '15 at 05:30
I believe this should be the accepted answer actually. This works for leap years also. +1vote – Tanzeel Jan 10 '20 at 06:07

Ninad Pingale · Answer 3 · 2017-06-14T15:05:55.133

Here is Regex for multiple date formats working for me :

        //dd.MM.yyyy
        var date_regex = /^(0[1-9]|1\d|2\d|3[01])\.(0[1-9]|1[0-2])\.(19|20)\d{2}$/;
        alert(date_regex.test("02.02.1991"));  

//      //dd/mm/yyyy
//      var date_regex = /^(0[1-9]|1\d|2\d|3[01])\/(0[1-9]|1[0-2])\/(19|20)\d{2}$/;
//          alert(date_regex.test("02/12/1991"));  

//      //dd-mm-yyyy
//      var date_regex = /^(0[1-9]|1\d|2\d|3[01])\-(0[1-9]|1[0-2])\-(19|20)\d{2}$/;
//      alert(date_regex.test("02-12-1991")); 

//      //mm/dd/yyyy
//      var date_regex = /^(0[1-9]|1[0-2])\/(0[1-9]|1\d|2\d|3[01])\/(19|20)\d{2}$/;
//      alert(date_regex.test("12/02/1991")); 


//      //yyyy.MM.dd
//      var date_regex = /^((19|20)\d{2})\.(0[1-9]|1[0-2])\.(0[1-9]|1\d|2\d|3[01])$/;
//      alert(date_regex.test("1991.12.02")); 

//      //yyyy/MM/dd
//      var date_regex = /^((19|20)\d{2})\/(0[1-9]|1[0-2])\/(0[1-9]|1\d|2\d|3[01])$/;
//      alert(date_regex.test("1991/12/02")); 

//      //yyyy-MM-dd
//      var date_regex = /^((19|20)\d{2})\-(0[1-9]|1[0-2])\-(0[1-9]|1\d|2\d|3[01])$/;
//      alert(date_regex.test("1991-12-02"));

score 4 · Answer 4 · answered Jan 20 '12 at 06:10

4

Try this:

'01-01-2012'.match( /\d{2}-\d{2}-\d{4}/ )

Note that that this way the date 33-12-2022 would be considered valid as well!

answered Jan 20 '12 at 06:10

zaphod1984

836
2
7
22

Dan · Answer 5 · 2012-03-04T07:11:17.720

3

'01-01-2012'.match( /(?!3[2-9]|00|02-3[01]|04-31|06-31|09-31|11-31)[0-3][0-9]-(?!1[3-9]|00)[01][0-9]-(?!10|28|29)[12][089][0-9][0-9]/ )

This looks for only valid dates from 1800 to 2099. No leap year support (as in it assumes every year is a possible leap year).

edited Mar 04 '12 at 07:11

answered Jan 20 '12 at 06:14

Dan

736
8
12

Davsket · Answer 6 · 2013-08-09T04:28:37.970

3

Well, I made this:

'31-12-1987'.match(/(3[01]|[2][0-9]|0\d)-(1[0-2]|0\[1-9])-\d{4}/)

Validates the day from 01 to 31, month from 01 to 12 and year of four digits. It only fails the february 30, and the months without 31 days. Which you can clean using the new Date('mm/dd/yyyy').

edited Aug 09 '13 at 04:28

answered Jan 20 '12 at 06:49

Davsket

1,248
1
9
14

for hijri date , there is no `31`ˢᵗ .. that's why , we remove `1` from `/3[01]....` to have : `/(3[0]|[2][0-9]|0\d)-(1[0-2]|0\[1-9])-\d{4}/` – Abdennour TOUMI Jan 12 '17 at 07:10

Rawat · Answer 7 · 2014-06-26T09:14:40.737

2

This regex is for MM/DD/YYYY and M/D/YYYY

var date_regex = /^(0?[1-9]|1[012])[\/](0?[1-9]|[12][0-9]|3[01])[\/]\d{4}$/;

edited Jun 26 '14 at 09:14

answered Jun 26 '14 at 09:07

Rawat

21
2

Jesse Sanford · Answer 8 · 2015-10-31T02:20:38.673

Working a few of the above together (primarily @gdZeus's) now you can do MM/dd/yyyy | MM-dd-yyyy | MM.dd.yyyy

/(^(((0[1-9]|1[012])[-/.](0[1-9]|1[0-9]|2[0-8]))|((0[13578]|1[02])[-/.](29|30|31))|((0[4,6,9]|11)[-/.](29|30)))[-/.](19|[2-9][0-9])\d\d$)|(^02[-/.]29[-/.](19|[2-9][0-9])(00|04|08|12|16|20|24|28|32|36|40|44|48|52|56|60|64|68|72|76|80|84|88|92|96)$)/

Additionally if you are using this inline in a js file you can use the following which returns a regexp literal. This will allow you to validate that a date is in the past! This is handy for birthdays. You can reverse it to check that a date is in the future as well (ex. checking credit card exp). This will work almost anywhere in javascript but not if you really need a regexp literal. For example if you are serializing it to a some other format without the ability to run js.

new RegExp('(^(((0[1-9]|1[012])[-/.](0[1-9]|1[0-9]|2[0-8]))|((0[13578]|1[02])[-/.](29|30|31))|((0[4,6,9]|11)[-/.](29|30)))[-/.]('+range(1920, new Date().getFullYear()).join('|')+')$)|(^02[-/.]29[-/.]('+range(1920, new Date().getFullYear()).filter(function(year){if (year % 4 == 0) { return true }}).join('|')+')$)/', 'g')

returns:

/(^(((0[1-9]|1[012])[-\/.](0[1-9]|1[0-9]|2[0-8]))|((0[13578]|1[02])[-\/.](29|30|31))|((0[4,6,9]|11)[-\/.](29|30)))[-\/.](1920|1921|1922|1923|1924|1925|1926|1927|1928|1929|1930|1931|1932|1933|1934|1935|1936|1937|1938|1939|1940|1941|1942|1943|1944|1945|1946|1947|1948|1949|1950|1951|1952|1953|1954|1955|1956|1957|1958|1959|1960|1961|1962|1963|1964|1965|1966|1967|1968|1969|1970|1971|1972|1973|1974|1975|1976|1977|1978|1979|1980|1981|1982|1983|1984|1985|1986|1987|1988|1989|1990|1991|1992|1993|1994|1995|1996|1997|1998|1999|2000|2001|2002|2003|2004|2005|2006|2007|2008|2009|2010|2011|2012|2013|2014|2015)$)|(^02[-\/.]29[-\/.](1920|1924|1928|1932|1936|1940|1944|1948|1952|1956|1960|1964|1968|1972|1976|1980|1984|1988|1992|1996|2000|2004|2008|2012)$)\//g

NOTE: this utilizes underscore's range function to generate the dates. You can write your own though like this very inelegant version :)

function range(start, end) {
  var foo = [];
  for (var i = start; i <= end; i++) {
    foo.push(i);
  }
  return foo;
}

score 0 · Answer 9 · edited Oct 13 '16 at 08:21

$('#DOB').blur(function ()   {
var s = $('#DOB').val();   alert('Entered date is:' + s);
var parms = s.split(/[\.\-\/]/);
var yyyy = parseInt(parms[2], 10);

var d = new Date();
var n = d.getFullYear(); //alert('current year is :' + n);
if (yyyy > n || yyyy < 1900) {
    alert('Improper date format, Please enter dd/mm/yyyy format. (invalid year)');
}
var mm = parseInt(parms[1], 10); 
if (mm > 12 || mm < 0)
{
    alert('Improper date format, Please enter dd/mm/yyyy format. (invalid month');
}
var dd = parseInt(parms[0], 10);
if (dd > 31 || dd < 0)
{
    alert('Improper date format, Please enter dd/mm/yyyy format. (invalid day');
}

//var date = new Date(dd, mm - 1, yyyy, 12, 0, 0, 0);
//var ndate = (date.getMonth() + 1) && ddmm === date.getDate() &&  yyyy === date.getFullYear();
// alert('new date is:' + ndate);
});

score 0 · Answer 10 · answered Oct 10 '18 at 06:13

0

This works for me

new RegExp('^(0[1-9]|[1-9]|[12][0-9]|3[01])-(0[1-9]|[1-9]|1[012])-(19|20)\\d\\d$')

answered Oct 10 '18 at 06:13

San Jaisy

15,327
34
171
290

score -2 · Answer 11 · answered Mar 06 '13 at 12:24

-2

/^(\d{1,2})(\/)(\d{1,2})\2(\d{4})\$/

answered Mar 06 '13 at 12:24

vks

9

Regular expression for date format- dd-mm-yyyy in Javascript

11 Answers11

Linked