How to test if $value is $num +-3

Question

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php if integer between a range?

Let's say $num = 5; How do I test if $value is anything in between +-3 of $num. In other words, how can I test if $value is equal to any of these values 2,3,4 5 6,7,8

score 9 · Accepted Answer · answered Jan 20 '12 at 08:51

9

Two possible ways to do it:

$num - 3 <= $value && value <= $num + 3
abs($num - $value) <= 3

answered Jan 20 '12 at 08:51

Lie Ryan

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score 2 · Answer 2 · answered Jan 20 '12 at 08:52

2

$mid = 5;
$range = 3;
$inRange = ($myval>=$mid-$range && $myval<=$mid+$range) ? TRUE : FALSE;

UPDATE I started throwin' out bass, she started throwin' back mid-range.

answered Jan 20 '12 at 08:52

Nobody else appreciated my **sweet** unintentional Biz Markie reference, I guess :) – Jan 20 '12 at 08:57

score 1 · Answer 3 · answered Jan 20 '12 at 08:51

1

if ($num - 3 <= $value && $value <= $num + 3)

answered Jan 20 '12 at 08:51

deceze

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score 1 · Answer 4 · answered Jan 20 '12 at 08:54

1

if ($value<=$num+3 && $value>=$num-3)
    echo "$value is between +-3 of $num";
else
    echo "$value is outside +-3 of $num";

answered Jan 20 '12 at 08:54

rauschen

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score 1 · Answer 5 · answered Jan 20 '12 at 09:23

1

try this:

$dif1 = $num - 3;
$dif2 = $num + 3;

if($dif1 <= $value){
       if($dif2 <= $value){
              echo "Your number in between +-3";
       }  
}

answered Jan 20 '12 at 09:23

Kichu

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score 0 · Answer 6 · answered Jan 20 '12 at 08:58

0

There is nothing big logic in this if you know the $num value take two variable $min and $max

set $min = $num - 3

set $max = $num + 3

and then with condition check your value..

$value > $min && $value < $max

answered Jan 20 '12 at 08:58

Murtaza

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How to test if $value is $num +-3

6 Answers6