xpath to find the node with maximum attributes

Question

I have an xml structure like this.

    <pages>
        <page a="1">111</page>
        <page a="1" b="2">222</page>
        <page a="1">333</page>
        <page a="1" b="2" c="3" d="4">444</page>
        <page a="1" b="2">555</page>
        <page a="1">666</page>
    </pages>

Xpath should return the value 444 since that node has got the maximum number of attributes. How can we do this? Please help.

score 1 · Answer 1 · edited May 23 '17 at 12:03

1

A similar question has already been asked and the conclusion is that it isn't really feasible yet. There doesn't seem to be a max() function in the current XPath specifications, so I think you'll have to apply some more complex code to get your answer... :)

edited May 23 '17 at 12:03

Community

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answered Jan 23 '12 at 13:36

FarligOpptreden

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score 1 · Accepted Answer · answered Jan 23 '12 at 14:14

1

According to http://wiki.orbeon.com/forms/doc/developer-guide/xpath-2-0-support Orbeon supports XPath 2.0 so you can do stuff like /pages/page[count(@*) eq max(/pages/page/count(@*))].

answered Jan 23 '12 at 14:14

Martin Honnen

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xpath to find the node with maximum attributes

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