LINQ to create int array of sequential numbers

Question

So instead of writing a looping function where you instantiate an array and then set each index value as the index, is there a way to do this in LINQ?

Possible duplicate of [How to create array with sequence of integers in C#?](http://stackoverflow.com/questions/4588787/how-to-create-array-with-sequence-of-integers-in-c) — Michael Freidgeim, Aug 04 '16 at 01:57

score 17 · Answer 1 · answered Jan 23 '12 at 20:27

You can use the System.Linq.Enumerable.Range method for this purpose.

Generates a sequence of integral numbers within a specified range.

For example:

var zeroToNineArray = Enumerable.Range(0, 10).ToArray();

will create an array of sequential integers with values in the inclusive range [0, 9].

Digbyswift · Accepted Answer · 2014-03-26T18:09:31.873

17

Enumerable.Range(0, 10) will give you an IEnumerable<int> containing zero to 9.

edited Mar 26 '14 at 18:09

answered Jan 23 '12 at 20:30

Digbyswift

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Actually that would be "zero to 9". The second parameter is a count. – Buzz Mar 26 '14 at 14:43

score 4 · Answer 3 · answered Jan 23 '12 at 20:30

4

You might want to look at Enumberable.Range

For Each( var i in Enumberable.Range(1,5).ToArray()){
    Console.WriteLine(i)
}

would print out 1,2,3,4,5

answered Jan 23 '12 at 20:30

acoffman

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LINQ to create int array of sequential numbers

3 Answers3