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I am trying to get the response from ajax call and save it in another value but wont work this is my code

x='go'
$.post("someurl",function(data){
    x=data;
})
alert(x)//go

or this jsFiddle

I am looking for a solution for this problem without storing the value in any HTML container

Evan Lévesque
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3 Answers3

6

$.post is asynchronous - the callback will be executed later, after your alert(x) line.

Try:

$.post("someurl",function(data){
    x=data;
    alert(x)
})

(No, there's no other way around this - you'll have to restructure your code accordingly. Don't be tempted to try setting async to false, or you'll end up with bigger problems).

James M
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0

In Javascript when you make this ajax call you are sending an Asynchronous call to the "someurl". This means your function continues and x remains undefined.

Solutions:

 $.post("someurl",function(data){
    //use your data here
});

or define a function outside

var myFunction = function (data){
  //do stuff with data
}

$.post("someurl",myFunction);
Maleck13
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why first declare x as a string and then put data in the same x? I think you should use json and have your php file parse it into json before sending back. Otherwise it just wont give a response. It will on check whether it has executed the call and that will always be "true" regardless of its succes.

Hope this helps.

BIEG

BIEG
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