I have reproduced this function:
function getTables()
{
global $db;
$value = array();
if (!($result = $db->query('SHOW TABLES'))) {
return false;
}
while ($row = $db->fetchrow($result)) {
if (empty($this->tables) or in_array($row[0], $this->tables)) {
$value[] = $row[0];
}
}
if (!sizeof($value)) {
$db->error("No tables found in database");
return false;
}
return $value;
}
in this manner:
public function getTables() {
$value = array();
$tables = array();
$sql = "SHOW TABLES";
if($stmt = $this->connect->prepare($sql)) {
$stmt->execute();
while( $row = $stmt->fetch_row() ) {
if(empty($tables) or in_array($row[0], $tables)) {
$value[0] = $row[0];
}
}
$stmt->close();
if(!sizeof($value)) {
echo 'The database has no tables';
}
return $value;
} else {
echo 'Couldn\t query the database';
}
}
But the second method returns me The database has no tables
which is not true because I have one table in the db.
What is it wrong with the second method ?
In case you wonder what connect
does :
public $connect;
public function __construct() {
// Define The Database Connection Or Die If Failed Connecting
$this->connect = new mysqli(DB_HOST, DB_USER, DB_PASS, DB_NAME) or die(DB_CONNECTION_ERROR_MESSAGE);
}
It make a connection with the database. And prepare()
it's a mysqli statement. I tried with query()
too, same result.