Why does making a class iterable produce this output?

Question

Possible Duplicate:
Why does defining getitem on a class make it iterable in python?

class b:
    def __getitem__(self, k):
        return k

cb = b()

for k in cb:
    print k

I get the output:

0
1
2
3
4
5
6
7
8
.....

Iterating over instance of class b, emits integers. Why is that?

(came across the above program when looking at Why does defining __getitem__ on a class make it iterable in python?)

Why did you post an exact duplicate of a question you linked to and was already perfectly answered there? — Rob Wouters, Feb 04 '12 at 22:47
@Rob In that post, i had some trouble figuring out as to why integers were being output — harish, Feb 04 '12 at 22:58
In hindsight, i should have looked at semantics of __getitem__ before posting this question — harish, Feb 04 '12 at 23:05

score 3 · Accepted Answer · answered Feb 04 '12 at 22:44

Because the for-loop is implemented for objects that define __getitem__ but not __iter__ by passing successive indices to the object's __getitem__ method. See the effbot. (What really happens under the covers IIUC is a bit more complicated: if the object doesn't provide __iter__, then iter is called on the object, and the iterator that iter returns does the calling of the underlying object's __getitem__.)

Why does making a class iterable produce this output?

1 Answers1