How to write a regexp with AND operator?

Question

I have definition string from my user to match an input string and i would like to simplify the definition string so my user won't need to know regexp internal.

my thought was to allow */-7721/-7722/-7723 to match any given 4 digit string which is not 7721 AND not 7722 AND not 7723.

I am searching for a regexp to perform the above on an input string which is a 4 digit number.

I have tried using the ?! notation, but it can't mis-match the entire string.

(?![0-9]{4}) - this doesn't allow any 4 digit string.

((?!(7721))(?!(7722))(?!(77223)) - this also didn't work

Is there an AND operator to perform the above?

Thanks,

In which programming language? Since these are numbers, can you use mathematics, rather than string operations? — johnsyweb, Feb 06 '12 at 13:33
@Johnsyweb: actually C++ boost regexp. let me update my tags. How can i use maths? (sorry for asking)? — NirMH, Feb 06 '12 at 13:34
?= perhaps? http://stackoverflow.com/questions/469913/regular-expressions-is-there-an-and-operator — Tim, Feb 06 '12 at 13:34
`int i = boost::lexical_cast(s); return i < 10000 && i != 7721 && i != 7722 && i != 7723;` — johnsyweb, Feb 06 '12 at 13:47

user1096188 · Accepted Answer · 2012-02-06T13:39:02.457

1

You forgot ^:

^(?!(?:7721))(?!(?:7722))(?!(?:7723))\d{4}

Edited: added \d{4} for actually matching the string, not just testing

edited Feb 06 '12 at 13:39

answered Feb 06 '12 at 13:33

user1096188

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What do you mean? Do you actually need to match the string, or merely test it? – user1096188 Feb 06 '12 at 13:37
The non-capturing subpatterns are unnecessary; also, this example can be simplified to `^(?!772[1-3])\d{4}$`. – cmbuckley Feb 06 '12 at 14:45

How to write a regexp with AND operator?

1 Answers1