Looking to fork a process, in c++, that wont hang its parent process - its parent is a daemon and must remain running. If i wait() on the forked process the forked execl wont defunt - but - it will also hang the app - not waiting fixes the app hang - but the command becomes defunt.
if((pid = fork()) < 0)
perror("Error with Fork()");
else if(pid > 0) {
//wait here will hang the execl in the parent
//dont wait will defunt the execl command
//---- wait(&pid);
return "";
} else {
struct rlimit rl;
int i;
if (rl.rlim_max == RLIM_INFINITY)
rl.rlim_max = 1024;
for (i = 0; (unsigned) i < rl.rlim_max; i++)
close(i);
if(execl("/bin/bash", "/bin/bash", "-c", "whoami", (char*) 0) < 0) perror("execl()");
exit(0);
}
How can I fork the execl without a wait(&pid) where execl's command wont defunct?
UPDATE Fixed by adding the following before the fork
signal(SIGCHLD, SIG_IGN);
Still working with my limited skills at a more compatible solution based on the accepted answer. Thanks!