how to change the image on a image button onmouseover event in HTML?

Question

I have 4 image button containing a image. on mouse over i have to change the image(i.e load a new image on the button). Here is the code.

<div class ="submit" id="submit" >
    <input  type="image" src="dump.png" value="Dumb" class ="Dumb" id="Dumb" onclick="posting_by_user('Dumb')" />
    <input  type="image" src="informative.png" value="Informative" class ="Informative" id="Informative" onclick="posting_by_user('Informative')"/>
    <input  type="image" src="brilliant.png" value="Brilliant" class ="Brilliant" id="Brilliant" onclick="posting_by_user('Brilliant')"/>
    <input  type="image" src="cool.png" value="Cool" class ="Cool" id="Cool" onclick="posting_by_user('Cool')"/>
</div>

Here I have loaded dump.png, informative.png, brilliant.png and cool.png. on mouse over on each button i have to change the image.

Possible answer? http://stackoverflow.com/questions/540349/change-the-image-source-using-jquery — Melros, Feb 07 '12 at 06:38

score 3 · Answer 1 · answered Feb 07 '12 at 06:47

3

Try this

$(document).ready(function() {
$('input[type=img]')
    .mouseover(function() { 
        var src =  "mouseover.png";
        $(this).attr("src", src);
    });

answered Feb 07 '12 at 06:47

Hemesh Singh

1,105
2
9
13

Vivek Chandra · Accepted Answer · 2012-02-07T06:48:51.777

2

<input  type="image" src="dump.png" value="Dumb" class ="Dumb" id="Dumb" onclick="posting_by_user('Dumb')" onmouseover="changeImg.call(this)" />

function changeImg(){
this.setAttribute("src","newImageFileName.jpg");
}

Segregating your code from html is always advised.. this answer will be helpful as it is cleaner and good for debugging..

edited Feb 07 '12 at 06:48

answered Feb 07 '12 at 06:40

Vivek Chandra

4,240
9
33
38

@raju.allen if you are new to stackoverflow,there is a tick mark next to each answer,you can accept an answer by clicking on that tick mark.. accept the answer which best suits/fixes your problem.. – Vivek Chandra Feb 07 '12 at 06:49

score 2 · Answer 3 · answered Feb 07 '12 at 06:42

2

<input  type="image" src="dump.png" value="Dumb" class ="Dumb" id="Dumb" 
onclick="posting_by_user('Dumb')" 
onmouseover="this.src='informative.png';" 
onmouseout="this.src='dump.png';" />

answered Feb 07 '12 at 06:42

amka

111
3

fardjad · Answer 4 · 2012-02-07T07:10:41.447

You can use either Javascript or CSS for this, below is the javascript approach.

window.addEventListener("load", function load (event) {
    window.removeEventListener("load", load, false);
    tieEvents();
}, false);

function tieEvents() {
    var button = document.getElementById('Dumb');

    button.addEventListener("mouseover", hovered, false);
    button.addEventListener("mouseout", unhovered, false);

    function hovered() {
        button.src = "anotherimg.png";
    }

    function unhovered() {
        button.src = "anotherimg.png";
    }
};

JSFiddle Demo

Note that setting events in HTML is not a good practice, it's better to tie them up in Javascript.

The CSS way is as follows:

#Dumb {
    backgroud: url("dump.png");
}

#Dumb:hover {
    backgroud: url("another.png");
}

JS Fiddle Demo

how to change the image on a image button onmouseover event in HTML?

4 Answers4