I'm looking for a pattern that accept only hebrew or english letters from 2 letters to 15, and can accept 1 space. I have tried following code but it does not matching my string:
<?php
$subject = "שלום לך";
$regexp="#^\p[{Hebrew}| ][a-zA-Z]{2,15}? \+$#u";
print_r(preg_match($regexp, $subject));
?>
There are multiple errors in your code.
First, your regex
$regexp="#^\p[{Hebrew}| ][a-zA-Z]{2,15}? \+$#u";
Here is what it means:
# : regex delimiter
^ : begining of string
\p : character p
[{Hebrew}| ] : character class, one of the char : {, H, e, b, r, w, }, |, space
[a-zA-Z]{2,15}? : from 2 to 15 alphabetic char
\+ : a space followed by +
$ : end of string
# : regex delimiter
u : unicode
Unicode hebrew char is : \p{Hebrew}
there no needs of | inside a char class
there is no + in your string, no space at the end
there no need to do ungreedy matching
so it sould be rewritten as:
$regexp="#^[\p{Hebrew} a-zA-Z]{2,15}$#u";
explanation:
# : regex delimiter
^ : begining of string
[ : start class character
\p{Hebrew} : a hebrew character
: a space
a-zA-Z : a latin letter
] : end of class
{2,15} : previous chars 2 to 15 times
$ : end of string
# : regex delimiter
u : unicode
preg_match doesn't return an array but an int that holds the number of time the pattern is found in the string.
Then your script becomes:
$subject = "שלום לך";
$regexp = "#^[\p{Hebrew} a-zA-Z]{2,15}$#u";
preg_match($regexp, $subject, $m);
print_r($m);
var regexp = /^[\u0591-\u05F4\s]+$/gi;
return regexp.test(str)
