Spring-enabled JAX-WS Web Service how to get client ip

Question

I use Spring 3.1 SimpleJaxWsServiceExporter to publish a webservice like this:

<bean class="org.springframework.remoting.jaxws.SimpleJaxWsServiceExporter" >
    <property name="baseAddress" value="http://192.168.1.8:8888/" /></bean>
    <bean id="webServiceEndpoint" class="com.test.remoting.jaxws.WebServiceEndpoint">
</bean>

then I try go get client ip, but my request is null, please tell me is there anythings wrong? thanks very much!!

@Resource  
WebServiceContext wsContext; 

@WebMethod
public String Test(){
    MessageContext mc = wsContext.getMessageContext();
    HttpServletRequest req = (HttpServletRequest)mc.get(MessageContext.SERVLET_REQUEST); //here is always null
    return "aa";
}

score 2 · Accepted Answer · answered Mar 13 '12 at 06:44

2

private String getIP(){
    MessageContext mc = wsContext.getMessageContext();
    HttpExchange exchange = (HttpExchange)mc.get("com.sun.xml.internal.ws.http.exchange");
    System.out.print(exchange.getRemoteAddress().getAddress().getHostAddress());
    return exchange.getRemoteAddress().getAddress().getHostAddress();
}

answered Mar 13 '12 at 06:44

Shelly Chen

85
2
11

Does this rely on the SUN JDK, what if the application is running on OpenJDK ? – abdelrahman-sinno Nov 19 '15 at 14:21
Unfortunately this doesn't work in my standalone application running on Jetty, HttpExchange is null. – abdelrahman-sinno Nov 19 '15 at 14:41

score 0 · Answer 2 · edited May 23 '17 at 10:27

0

If the MessageContext.SERVLET_REQUEST or HttpExchange don't work. You can use a j2e filter or RequestListener

See https://stackoverflow.com/a/139169/2257772

edited May 23 '17 at 10:27

Community

1
1

answered Nov 26 '15 at 09:51

benbenw

723
7
20

Bounty awarded since it's ending, however I still have to try this out. Thanks. – abdelrahman-sinno Nov 26 '15 at 10:11

Spring-enabled JAX-WS Web Service how to get client ip

2 Answers2