Read File on Networkshare

Question

I am running my Application from a network-share. For example: "\server\startProgramm.bat" The Code in my startProgramm.bat:

java -jar %~dp0\app.jar

I need to open some config files. It is working local if i try to open them with:

new File("").getAbsolutePath() + "\\" + filename

but not on my Network share.

The config-files are in a subdir of the dir where my jar and bat files are.

how about `new File("\\\\servername\\sharedDirectoryOnServer\\fileOnServer")` ? — Bernd Elkemann, Feb 13 '12 at 08:20
Ok, this worked, but is there something like CurrentWorkDir? — jussi, Feb 13 '12 at 08:32
I guess you are getting a FileNotFoundException? Maybe the issue is related to that directory name? Try printing the path your program tries to read when running from that network share. — TPete, Feb 13 '12 at 08:43
Ok, i copied my comment to an answer for future reference and added what i found about the working directory — Bernd Elkemann, Feb 13 '12 at 08:48

score 0 · Accepted Answer · edited May 23 '17 at 12:11

new File("\\\\servername\\sharedDirectoryOnServer\\fileOnServer");

"Ok, this worked, but is there something like CurrentWorkDir?"

The current working directory is (by default) the one your program runs in. You can not change it within java (see here: Changing the current working directory in Java? ), the best practice is to just concatenate the server-path and file-name; but i think (not sure) it is also possible to start your program from the server (java \\server\\path\\myprog where there's a myprog.class in that directory) and make the working directory default to that path.

Read File on Networkshare

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