is there any way to define objects in hibernate.cfg.xml by scope and not one by one?
For example, in Spring you can define all controllers by such annotation:
<context:component-scan base-package="crm.controller" />
Can I define hibernate classes in the same way? Or it must be defined one by one?
Thank you
If you are using Spring MVC, you can configure it when setting up your sessionFactory. If you are using hbm files:
<bean id="sessionFactory" class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="mappingResources">
<list>
<value>file1.hbm.xml</value>
<value>file2.hbm.xml</value>
</list>
</property>
<property name="hibernateProperties" ref="hibernateProperties"/>
</bean>
If you are using annotated classes:
<bean id="sessionFactory" class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="packagesToScan" value="com.me.domain">
<property name="hibernateProperties" ref="hibernateProperties"/>
</bean>
Why dont you try this . I have this configured in springDAOcontext.xml
<bean id="csiSessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">
<property name="configLocation">
<value>classpath:hibernate/hibernate.cfg.xml</value>
</property>
<property name="dataSource" ref="DataSource"/>
<property name="mappingResources">
<list>
<value>hibernate/*</value>
</list>
<property>
As far as I can remember, Hibernate as it is out-of-the box, does not support "package-sanning" to discover your domain classes.
But given that you're integrating Hibernate with Spring MVC, you could annotate your classes (standard JPA + Hibernate specific annotations) and within your Spring context configuration file, specify the package that contains the Hibernate entity classes. Here's how I configured it in a previous project :
<bean id="sessionFactory"
class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="packagesToScan" value="org.springmvc.domain" />
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.HSQLDialect</prop>
<prop key="hibernate.hbm2ddl.auto">update</prop>
<prop key="show_sql">true</prop>
<prop key="log_level">DEBUG</prop>
</props>
</property>
</bean>
The "packagesToScan" property define the packages that Spring will have Hibernate scan to discover the entity classes.
im use jpa annotation @Entity,the code of applicationContext.xml is :
<bean id="sessionFactory"
class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="packagesToScan" value="com.yourcompany.module" />
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">${hibernate.dialect}</prop>
<prop key="hibernate.show_sql">${hibernate.show_sql}</prop>
</props>
</property>
</bean>
The package path "com.yourcompany.module" is your java entity package,for example:
package com.yourcompany.module;
@Entity
class MyEntity{
private Long id;
set get...
}
Try using:
<mapping package="com.mycompany.model" />
instead of a set of elements:
<mapping class="com.mycompany.model.EntytyOne" />
<mapping class="com.mycompany.model.EntytyTwo" />
