Where do I modify the admin view code for a 3rd party app?

Question

I am using a 3rd party app in my django webapp. But I want to customize the admin view for one of the models in the 3rd party app. The customization is more than changing the change_list.html template i.e. I will need to add code to talk to an external webservice etc.

However, I don't want to modify the 3rd party app. Instead I want to override it. How I override the ModelAdmin for a model that comes from a 3rd party app ?

score 42 · Accepted Answer · edited May 23 '17 at 12:10

42

This should get you started:

from django.contrib import admin
from thirdpartyapp.models import ThirdPartyModel
from thirdpartyapp.admin import ThirdPartyAdmin

class CustomThirdPartyAdmin(ThirdPartyAdmin):
    pass


admin.site.unregister(ThirdPartyModel)
admin.site.register(ThirdPartyModel, CustomThirdPartyAdmin)

I use this often to customize the UserAdmin as shown in this answer.

edited May 23 '17 at 12:10

Community

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answered Feb 17 '12 at 02:14

Trey Hunner

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Where should this code go? In a new folder inside project main folder with the `thirdpartyapp` name? – kahlo Jul 05 '14 at 10:18
3

In an admin.py file in one of your apps. – Trey Hunner Jul 08 '14 at 22:58
this is also useful if you need to register a custom model instead of the original. – Paolo Nov 09 '18 at 16:48

score 2 · Answer 2 · answered Jun 10 '23 at 12:06

Several years later, for those experiencing this issue, the solution is in this link .

However fore newbies like me, a little bit more explanation on how to implement it is in place.

First, the issue happened in Postgres (at least to me) and not in Sqlite, for some reason I was not able to delete users in Postgres, furthermore this started happening after I set up an email server and set up the user validation with Djoser through email. I was not able to find the root cause, there are some really old bugs pointing to this issue, but they exceed me.

The solution is in the linked answer:

from rest_framework_simplejwt import token_blacklist

class OutstandingTokenAdmin(token_blacklist.admin.OutstandingTokenAdmin):

    def has_delete_permission(self, *args, **kwargs):
        return True # or whatever logic you want

admin.site.unregister(token_blacklist.models.OutstandingToken)
admin.site.register(token_blacklist.models.OutstandingToken, OutstandingTokenAdmin)

This code should be inside the app you created for your users inside the admin.py file. It shouldn't be in the rest_framework token blacklist admin.py file.

If you face the 'rest_framework_simplejwt.token_blacklist' has no attribute 'admin' issue, it is simply because you are importing incorrectly.

What I did was change the import statement to work with my code as follows:

from rest_framework_simplejwt.token_blacklist import admin as tokadmin
from rest_framework_simplejwt.token_blacklist import models as tokmodels
class OutstandingTokenAdmin(tokadmin.OutstandingTokenAdmin):

def has_delete_permission(self, *args, **kwargs):
    return True # or whatever logic you want

admin.site.unregister(tokmodels.OutstandingToken)
admin.site.register(tokmodels.OutstandingToken, OutstandingTokenAdmin)

score 0 · Answer 3 · answered Dec 02 '22 at 22:27

For those who after put the code on any app/admin.py file, and get this error:

django.contrib.admin.sites.NotRegistered: The model <MODEL_APP_NAME> is not registered

You need to change the name of the admin view for example adding "Custom<Model_NAME>Admin" I think there are conflicts using the same model admin name. With that solution removes the error.

Where do I modify the admin view code for a 3rd party app?

3 Answers3

Linked