How do I add basic authentication for the default client of the httpClient library? I have seen examples where they use client.getCredentialProvider()
, however I think all of this methods are for library version 4.0.1 or 3.x. Is there a new example of how to do this? Thanks a lot.
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1Please see http://hc.apache.org/httpcomponents-client-ga/tutorial/html/authentication.html http://hc.apache.org/httpcomponents-client-ga/examples.html – ok2c Feb 23 '12 at 09:58
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This is the best example I've found anywhere... way better than the apache documentation : http://stackoverflow.com/a/4328694/967980 – Erich Apr 16 '15 at 19:22
6 Answers
CredentialsProvider credentialsProvider = new BasicCredentialsProvider();
credentialsProvider.setCredentials(AuthScope.ANY,
new UsernamePasswordCredentials("username", "password"));
CloseableHttpClient httpClient =
HttpClientBuilder.create().setDefaultCredentialsProvider(credentialsProvider).build();

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6This is the best answer for v4.3. Just be careful that it will send the credentials preemptively to *all* URLs. – artbristol Mar 26 '14 at 19:34
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5
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@artbristol Only if you have preemptive auth configured, right? ["HttpClient does not support preemptive authentication out of the box"](https://hc.apache.org/httpcomponents-client-ga/tutorial/html/authentication.html) – bmaupin Apr 07 '20 at 20:17
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@bmaupin yes I think you're right. This will send the credentials to any server that demands them, but not otherwise. – artbristol Apr 15 '20 at 07:40
Didn't you download the example from the website?And examples are here: httpcomponents-client-4.1.3\examples\org\apache\http\examples\client
As for https,Just see ClientAuthentication.java:
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* contributor license agreements. See the NOTICE file distributed with
* this work for additional information regarding copyright ownership.
* The ASF licenses this file to You under the Apache License, Version 2.0
* (the "License"); you may not use this file except in compliance with
* the License. You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing, software
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* <http://www.apache.org/>.
*/
package org.apache.http.examples.client;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.auth.AuthScope;
import org.apache.http.auth.UsernamePasswordCredentials;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.util.EntityUtils;
/**
* A simple example that uses HttpClient to execute an HTTP request against
* a target site that requires user authentication.
*/
public class ClientAuthentication {
public static void main(String[] args) throws Exception {
DefaultHttpClient httpclient = new DefaultHttpClient();
try {
httpclient.getCredentialsProvider().setCredentials(
new AuthScope("localhost", 443),
new UsernamePasswordCredentials("username", "password"));
HttpGet httpget = new HttpGet("https://localhost/protected");
System.out.println("executing request" + httpget.getRequestLine());
HttpResponse response = httpclient.execute(httpget);
HttpEntity entity = response.getEntity();
System.out.println("----------------------------------------");
System.out.println(response.getStatusLine());
if (entity != null) {
System.out.println("Response content length: " + entity.getContentLength());
}
EntityUtils.consume(entity);
} finally {
// When HttpClient instance is no longer needed,
// shut down the connection manager to ensure
// immediate deallocation of all system resources
httpclient.getConnectionManager().shutdown();
}
}
}
So in short :
DefaultHttpClient httpclient = new DefaultHttpClient();
httpclient.getCredentialsProvider().setCredentials(
new AuthScope("localhost", 443),
new UsernamePasswordCredentials("username", "password"));
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8DefaultHttpClient is deprecated in 4.x. You can use an example https://hc.apache.org/httpcomponents-client-ga/httpclient/examples/org/apache/http/examples/client/ClientAuthentication.java from https://hc.apache.org/httpcomponents-client-ga/examples.html . – Xdg Jul 28 '14 at 05:43
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1DefaultHttpClient has been deprecated only in 4.3. It is not deprecated in 4.1 – Marco Altieri Jun 25 '16 at 14:19
Another modern option for 4.3 is to use the Fluent extension:
Executor executor = Executor.newInstance()
.auth(new HttpHost("somehost"), "username", "password")
.auth(new HttpHost("securehost", 443, "https"), "username", "password") // https example
.auth(new HttpHost("myproxy", 8080), "username", "password")
.authPreemptive(new HttpHost("myproxy", 8080));
String content = executor.execute(Request.Get("http://somehost/"))
.returnContent().asString();

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3Having struggle a bit to make this work on an https connection, one need no to forget to add port and scheme on HttpHost (new HttpHost("somehost", 443, "https"), as default port and scheme are 80, http. – Olivier Jan 28 '16 at 13:22
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What is the full import path for `Executer`? I'm getting an error for `.newInstance()`. Compiler says that doesn't exist. Which version of JDK are you using? – Robert Reiz Jun 27 '17 at 07:45
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`org.apache.http.client.fluent.Executor` http://hc.apache.org/httpcomponents-client-ga/fluent-hc/apidocs/org/apache/http/client/fluent/Executor.html – Barett Jun 27 '17 at 07:49
DefaultHttpClient has getCredentialsProvider() but HttpClient doesn't. You need to declare DefaultHttpClient client = ... instead of HttpClient client = ...

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8`DefaultHttpClient` is now deprecated in 4.3, despite only being introduced in 4.0! – artbristol Mar 26 '14 at 19:35
I had this requirement of invoking a URL with Basic Authentication which also required proxy settings. This is what worked for me.
import java.io.IOException;
import java.io.InputStream;
import java.io.StringReader;
import java.util.HashMap;
import java.util.Map;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.apache.commons.httpclient.Credentials;
import org.apache.commons.httpclient.HostConfiguration;
import org.apache.commons.httpclient.HttpClient;
import org.apache.commons.httpclient.HttpMethod;
import org.apache.commons.httpclient.HttpStatus;
import org.apache.commons.httpclient.UsernamePasswordCredentials;
import org.apache.commons.httpclient.auth.AuthScope;
import org.apache.commons.httpclient.methods.GetMethod;
import org.w3c.dom.*;
import javax.xml.parsers.*;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;
public class TestResponse {
public final static String TESTURL="https://myURL";
private static final String PROXY_HOST = "www2.proxyXYS";
private static final int PROXY_PORT = 8080;
public static void main (String args[])
{
HttpClient client = new HttpClient();
HttpMethod method = new GetMethod(TESTURL);
HostConfiguration config = client.getHostConfiguration();
config.setProxy(PROXY_HOST, PROXY_PORT);
String username = "User";
String password = "Pa55w0rd";
Credentials credentials = new UsernamePasswordCredentials(username, password);
AuthScope authScope = new AuthScope(PROXY_HOST, PROXY_PORT);
client.getState().setProxyCredentials(authScope, credentials);
client.getState().setCredentials(AuthScope.ANY, credentials);
try {
client.executeMethod(method);
String response = method.getResponseBodyAsString();
if (method.getStatusCode() == HttpStatus.SC_OK) {
response = method.getResponseBodyAsString();
}
} catch (IOException e) {
e.printStackTrace();
} finally {
method.releaseConnection();
}
}
}

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We do basic authentication with HttpClient
, but we do not use CredentialProvider
. Here's the code:
HttpClient client = factory.getHttpClient(); //or any method to get a client instance
Credentials credentials = new UsernamePasswordCredentials(username, password);
client.getState().setCredentials(AuthScope.ANY, credentials);
UPDATE:
A stated in the comments, the HttpClient.getState()
methos is available in version 3.x of the API. However, newer versions of the API doesn't support that method.

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33That's great, but HttpClient.getState() doesn't exist in the 4.x code. This is only applicable for 3.1 and earlier. – Spanky Quigman Nov 02 '12 at 18:34
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12Am I the only one confused as to why this is the accepted answer? – Kartik Chugh Nov 03 '16 at 14:36