Great, thanks. I was trying `zip((a,b,c))` which was giving me something else.
– David542Mar 06 '12 at 19:53
2
if you have a tuple of the lists, i.e. `(a, b, c)`, you can pass it to `zip` like so: `d = zip(*(a, b, c))`. This unpacks the tuple `(a, b, c)` to pass them as arguments to `zip`.
For python 3.x, zip provides a generator, and you should use `d = tuple(zip(a, b, c))` to get `d = ([1,3,5],[2,4,6])`.
– Casey KuballMar 06 '12 at 20:04