How do I get a list of function instances for a python source file?

Question

Let's say I have a file called example.py with the following content:

def func_one(a):
    return 1

def func_two(b):
    return 2

def func_three(b):
    return 3

How would I get a list of function instances for that file? I have tried playing with the compiler,parser and ast modules but I can't really figure it out. It might be a lot easier than that, but it's slightly out of my depth.

EDIT: To be clear I don't want to import the functions.

Tkae a look: http://stackoverflow.com/questions/139180/listing-all-functions-in-a-python-module — MByD, Mar 12 '12 at 07:27
nah i dont want to import it. i just want access to the function itself. — Glen Robertson, Mar 12 '12 at 07:29
Without actually importing the module, the problem is much harder (and you'll miss things like import-time actions that populate the module's namespace without using the `def` keyword, unless you implement your own Python language...). — torek, Mar 12 '12 at 07:37

score 4 · Accepted Answer · answered Mar 12 '12 at 07:29

4

You can use inspect module:

>>> import inspect
>>> import example
>>> inspect.getmembers(example, inspect.isroutine)
[('func_one', <function func_one at 0x0238CBB0>), ('func_three', <functi
three at 0x0240ADB0>), ('func_two', <function func_two at 0x0240ADF0>)]

answered Mar 12 '12 at 07:29

Mikhail Churbanov

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yeah i don't want to import it though. – Glen Robertson Mar 12 '12 at 07:31
that's close i think. i want to do that without actually importing it – Glen Robertson Mar 12 '12 at 07:32
How do you wanna do it then? I mean at least the file will be imported if not the functions. What is your use case? – spicavigo Mar 12 '12 at 07:35
well i guess i could import them, but i don't want the functions to be callable from the interpreter and pollute the local namespace. – Glen Robertson Mar 12 '12 at 07:39
local namespace will only have the name of the module you imported. Not the functions which reside in it. The functions need to be qualified with the module name still. – spicavigo Mar 12 '12 at 07:40
ah you're right. sorry i was slightly confused but i understand now. thanks this one will work! :) – Glen Robertson Mar 12 '12 at 07:42
... If you don't want the functions to be usable, then why do you care what they are? – Karl Knechtel Mar 12 '12 at 10:30
i am inspecting them for something but i do not want to execute them. – Glen Robertson Mar 12 '12 at 16:57

score 0 · Answer 2 · answered Mar 12 '12 at 07:27

You can use dir. This return the list of names in the current local scope. Although this might return more than function names.

>>> import utils
>>> utils.__name__
'utils'
>>> dir(utils)
['__builtins__', '__doc__', '__file__', '__name__', '__package__', 'human_number', 'islice', 'math', 'prime_factors', 'primes_sieve', 'primes_sieve1', 'proper_divisors', 'pyth_triplet', 'square_of_sum', 'sum_of_nums', 'sum_of_squares', 'test', 'triangle_nums', 'window']

fraxel · Answer 3 · 2012-03-12T07:43:43.953

0

If you really don't want to import into the namespace like this:

import examples
print dir(examples)

['__builtins__', '__doc__', '__file__', '__name__', 
'__package__', 'func_one', 'func_three', 'func_two'] #OUTPUT

You could open and read the file, doing a search for any defs and append those to a list, thus returning all function, and method definition names.

edited Mar 12 '12 at 07:43

answered Mar 12 '12 at 07:28

fraxel

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score 0 · Answer 4 · answered Mar 12 '12 at 07:32

0

You could use globals() function, it is return a dict with all global environment where you can find you functions. Example:

d = globals().copy()
l = []
[l.append(k) for k in d if k.startswith('func')]

answered Mar 12 '12 at 07:32

Denis

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How do I get a list of function instances for a python source file?

4 Answers4