PHP simple date format

Question

I have a date that I need to convert using PHP date. I've tried a couple different things with no success.

Date coming in: 2011/10/14

Date I need going out: October 2011

Do I need to convert my incoming date to time, and then from time to date going out? I don't understand.

possible duplicate of [Convert date/time (PHP)](http://stackoverflow.com/questions/2412402/convert-date-time-php) Virtually all questions about converting dates in PHP can be solved by `strtotime()` or `mktime()` or the `DateTime` class. Some more resources: http://stackoverflow.com/search?q=php+convert+date — Wesley Murch, Mar 12 '12 at 19:30
No need to convert it to time: http://php.net/manual/en/book.datetime.php — PeeHaa, Mar 12 '12 at 19:31

score 6 · Accepted Answer · answered Mar 12 '12 at 19:31

6

You can use DateTime and its format() method:

$date = new DateTime('2011/10/14');
echo $date->format('F Y');

answered Mar 12 '12 at 19:31

Gergo Erdosi

score 3 · Answer 2 · answered Mar 12 '12 at 19:30

3

date("F Y", strtotime($date));

answered Mar 12 '12 at 19:30

ThePrimeagen

score 0 · Answer 3 · answered Mar 12 '12 at 19:31

0

$date_out = date("F Y", strtotime($date_in));

strtotime converts a string value to a timestamp.

date converts a timestamp into a string representation based on the format provided as the first argument.

answered Mar 12 '12 at 19:31

danielrsmith

score 0 · Answer 4 · answered Mar 12 '12 at 19:32

0

You can almost certainly accomplish that and pretty much almost problem related to date/time convertion using the DateTime class of PHP core.

answered Mar 12 '12 at 19:32

Daniel Ribeiro

4 Answers4