$.ajax URL inquiry

Question

Will toDistance.php ran after calling this function? It seems like toDistance.php is not called. Thanks

function myAjax(volunteerDist, jid){
            $.ajax({
            type:'POST',
            url: 'toDistance.php',
            data : ({
                distance:volunteerDist,
                id:jid
            }),
            success: function(){
                 alert('worked');
            },
               error :function(jqXHR, textStatus, errorThrown) {
                alert(errorThrown);
            },
           complete : function(){
               alert('thanks');
           }
        });

@JoeTuskan in my toDistance.php, I had an echo, but it did not do so, how come? — Brandon Young, Mar 15 '12 at 18:00
@JoeTuskan okay, now, volunteerDist and jid are arrays, how can I $_GET it in my toDistance.php? — Brandon Young, Mar 15 '12 at 18:02
You need to make more "home-work" before posting a question. **What do you see in firebug?** stackoverflow isn't a "charades game" kind of place — gdoron, Mar 15 '12 at 18:04
i am sorry.. i do not know firebug.. it just knew about this today and read about this $_GET — Brandon Young, Mar 15 '12 at 18:08
SO, if you already know firebug, fiddler, etc. what do you see in there? See this ->http://stackoverflow.com/questions/4263116/wireshark-vs-firebug-vs-fiddler-pros-and-cons — jose, Mar 16 '12 at 09:24

score 1 · Accepted Answer · answered Mar 15 '12 at 18:01

1

Did you tried out by taking arguments on your success function? Try this code.

function myAjax(volunteerDist, jid){
            $.ajax({
            type:'POST',
            url: 'toDistance.php',
            success: function( data ){
            ///CHECK UR UPCOMING DATA
                 alert(data.jid);
                 alert('worked');
            },
               error :function(jqXHR, textStatus, errorThrown) {
                alert(errorThrown);
            },
           complete : function(){
               alert('thanks');
           }
        });

answered Mar 15 '12 at 18:01

Hamza Waqas

629
4
12

it says undefined.. what does that mean? – Brandon Young Mar 15 '12 at 18:06
does it ouput undefined before printing 'worked' ? Looks like your script isn't returning any data – jose Mar 15 '12 at 18:07
okay, but how can that be? before I called myAjax(volunteerDist, jid); i printed their values and the results are there – Brandon Young Mar 15 '12 at 18:09
@jose i alerted (volunteerDist) and it alerted all the values inside – Brandon Young Mar 15 '12 at 18:15
try by alert the full object and see what is returns. Object or null alert. – Hamza Waqas Mar 16 '12 at 11:23

score 0 · Answer 2 · answered Mar 15 '12 at 18:00

0

Will toDistance.php ran after calling this function?

If the data parameter is what the server expecting to get, Yes.

Use firebug, check what is going on with your request and stop guessing...

answered Mar 15 '12 at 18:00

gdoron

147,333
58
291
367

score 0 · Answer 3 · answered Mar 15 '12 at 18:00

0

It seems OK. Try to track web traffic with FIddler and check if the script is called and the arguments.

If you're debbuging with Safari, Chrome or Firefox you can record the traffic. Check for POST variables, script location etc.

answered Mar 15 '12 at 18:00

jose

2,733
4
37
51

$.ajax URL inquiry

3 Answers3