Listview getFirstVisiblePosition

Question

I am trying to get the position of the first visible row that is entirely visible to screen. End of scrolling, if the portion of the row is visible in first row, I need to select next position. How to do this?

score 2 · Answer 1 · edited May 23 '17 at 12:00

2

int index = list.getFirstVisiblePosition();
View v = list.getChildAt(0);
int y = (v == null) ? 0 : v.getTop();

if (y > 0 && index + 1 < list.getCount()) {
    ++index;
}

Adapted from this answer.

edited May 23 '17 at 12:00

Community

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answered Mar 18 '12 at 11:07

Dheeraj Vepakomma

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This seems to work for me. But still I needed only the value for "y". So I didn't try the last if condition.Apart from that, the condition seems to work fine. – Andro Selva Apr 10 '12 at 08:15

score 0 · Answer 2 · answered Mar 17 '12 at 22:31

0

youe need to implement OnScrollListener on your ListView and then override the following method to get the first visible item:

@Override
public void onScroll(AbsListView view, int firstVisibleItem, final int visibleItemCount, final int totalItemCount) {
    //"firstVisibleItem" is the value you need to look for
}

answered Mar 17 '12 at 22:31

waqaslam

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but i want to check ,whether the user can see the first row (firstVisibleItem) entirely. for example when you started scroll a list, you can see only little part in first row & last row. if you want to see entire portion of the first/bottom row, you need to scroll it up/down little future. – Jram Mar 17 '12 at 22:44
as long as even 1dp of an item is visible, it is considered as visible by `firstVisibleItem` – waqaslam Mar 17 '12 at 23:19

Listview getFirstVisiblePosition

2 Answers2