In my previous question, I reported that a keyboard hook was reporting everything twice when scanning a barcode.
I put that down to key down & key events and received good advice.
Having looked at it more closely I find that each digit is actually being report FOUR times!
Here's a crude "debug by print". Can anyone suggest what I might be doing wrong? Do you need more info? I could just ignore every second input, but ... yeuck! I would rather understand what is happening.
Here's what I got for a single digit 2
---------
LongParam = 196609 | Word = 50 | 2
LongParam and $80000000 = 0
LongParam and $40000000 = 0
---------
LongParam = 196609 | Word = 50 | 2
LongParam and $80000000 = 0
LongParam and $40000000 = 0
---------
LongParam = -1073545215 | Word = 50 | 2
LongParam and $80000000 = 2147483648
LongParam and $40000000 = 1073741824
---------
LongParam = -1073545215 | Word = 50 | 2
LongParam and $80000000 = 2147483648
LongParam and $40000000 = 1073741824
Update: here's my code
function KeyboardHookProc(Code: Integer; WordParam: Word; LongParam: LongInt): LongInt; stdcall;
begin
if Code < 0 then // http://msdn.microsoft.com/enus/library/windows/desktop/ms644984%28v=vs.85%29.aspx
begin
Result := CallNextHookEx(KBHook, Code, WordParam, LongParam);
Exit;
end;
MainForm.Memo1.Lines.Add('---------');
MainForm.Memo1.Lines.Add('LongParam = ' + IntToStr(LongParam) + ' | Word = ' + IntToStr(Ord(WordParam)) + ' | ' + Char(WordParam));
MainForm.Memo1.Lines.Add('LongParam and $80000000 = ' + IntToStr(LongParam and $80000000));
MainForm.Memo1.Lines.Add('LongParam and $40000000 = ' + IntToStr(LongParam and $40000000));
if ((LongParam and $80000000) <> $80000000) (* not key up *)
or ((LongParam and $40000000) <> $40000000) (* key was not previously down *)
then
begin
Result := CallNextHookEx(KBHook, Code, WordParam, LongParam);
Exit;
end;
if MainForm.ScanningChemical = False then
begin
Result := CallNextHookEx(KBHook, Code, WordParam, LongParam);
Exit;
end;
At this point I have a bar code digit. But those memo lines were added before here.