I want to initialize an array of int and populate it with a range of numbers:
return new int[].Populate(30,50);
So then I would have an array with 30, 31, 32, 33... - 50
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You can use Enumerable.Range() to e.g. return an array of 21 integers starting at 30:
return Enumerable.Range(30, 21).ToArray();
BrokenGlass
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1You need to extend the count to 21 (it includes the starting number). – Justin Niessner Mar 27 '12 at 23:05
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Use Enumerable.Range
var array = Enumerable.Range(30, 21).ToArray();
This will result in a sequence of 21 values starting at 30. Simply put, you get your { 30 ... 50 } array.
Anthony Pegram
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2@phoog If somebody already knows the answer, it will save him some time to set up a project to test it – Denny Sep 19 '16 at 18:34
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Using a for loop is actually faster than using Enumerable.Range().ToArray()
I measured it for creating an array of 1 000 000 elements.
int[] array = Enumerable.Range(0, 1000000).ToArray(); takes 9ms, while creating an array int[] array2 = new int[1000000]; and filling it in a for loop took only 3ms.
adam
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This seems not to be the case anymore. My measurement of Enumerable.Range().ToArray() of 100 000 000 elements took around 1170 ms, and filling the same amount of elements in `new int[]` in a loop took around 6900 ms. – Jogge Aug 16 '22 at 08:19