Window Startup Location from resource dictionary

Question

I'm trying to set all my windows to open in the center of the screen. All my windows use style file:

    <Window.Resources>
    <ResourceDictionary>
        <ResourceDictionary.MergedDictionaries>
            <ResourceDictionary Source="../Styles/Mystyles.xaml"/>
        </ResourceDictionary.MergedDictionaries>
    </ResourceDictionary>
</Window.Resources>

So I just inserted this property to the resource dictionary:

    <Style x:Key="windowStyle" TargetType="Window">
         <Setter Property="WindowStartupLocation" Value="CenterScreen"/>
    </Style>

But, it doesn't work. Am I missing something?

`WindowStartupLocation` is a CLR property, in the style setters can only be specified dependency property. See my [answer](http://stackoverflow.com/questions/10596515/setting-windowstartuplocation-from-resourcedictionary-throws-xamlparseexception/21178555#21178555). — Anatoliy Nikolaev, Jan 17 '14 at 05:38
Does this answer your question? [Setting WindowStartupLocation from ResourceDictionary throws XamlParseException](https://stackoverflow.com/questions/10596515/setting-windowstartuplocation-from-resourcedictionary-throws-xamlparseexception) — StayOnTarget, Sep 16 '22 at 16:51

Ron.B.I · Answer 1 · 2013-06-01T06:51:59.533

1

You cannot use a Style to define WindowStartupLocation, this is due to the fact that it is not a dependency property. You can define a StaticResource in your resource dictionary which you will use in your windows:

<WindowStartupLocation x:Key="StartupLocation">CenterScreen</WindowStartupLocation>

and then use it like so:

WindowStartupLocation="{DynamicResource StartupLocation}"

edited Jun 01 '13 at 06:51

answered May 31 '13 at 19:48

Ron.B.I

2,726
1
20
27

score 0 · Answer 2 · answered Feb 22 '17 at 12:03

To make every start every window at Center Screen Add this line in App.xaml

<Application.Resources>
        <WindowStartupLocation x:Key="StartupLocation">CenterScreen</WindowStartupLocation>
</Application.Resources>

and add this line in Window tag

WindowStartupLocation="{StaticResource StartupLocation}"

score 0 · Answer 3 · answered Apr 02 '12 at 12:10

0

You don't need to use x:Key attribute. Your style must look like this:

<Style TargetType="{x:Type Window}">
    <Setter Property="WindowStartupLocation" Value="CenterScreen"/>
</Style>

answered Apr 02 '12 at 12:10

bniwredyc

8,649
1
39
52

score 0 · Answer 4 · answered Apr 02 '12 at 12:49

if you dont want to use implicit styles (as bniwredyc suggested) you must set style explicitly:

<Window **Style="{StaticResource windowStyle}"**>
<Window.Resources>
    <ResourceDictionary>
        <ResourceDictionary.MergedDictionaries>
            <ResourceDictionary Source="../Styles/Mystyles.xaml"/>
        </ResourceDictionary.MergedDictionaries>
    </ResourceDictionary>
</Window.Resources>

Window Startup Location from resource dictionary

4 Answers4

Linked