Questions tagged [xmlroot]
34 questions
15
votes
1 answer
Difference between using XMLRoot/XMLElement and using Serializable() attributes (in c#)
what is Difference between using XMLRoot/XMLElement and using Serializable() attributes?
how do i know when to use each ?
Rodniko
- 4,926
- 20
- 69
- 93
15
votes
4 answers
XmlRoot() for Xml Serilization does not work
I'm trying to get my httphandler to print out an XML file with the format:
...
...
…
burnt1ce
- 14,387
- 33
- 102
- 162
11
votes
3 answers
Get attribute names and values from ElementTree
I have an XML element with several attributes. I've been using the ElementTree package.
After I've parsed a tree from an xml file, I'm getting the document root, but I want to get the requested attribute, or even the entire list of…
Igal
- 4,603
- 14
- 41
- 66
5
votes
1 answer
error in marshalling - missing xmlrootelement annotation error
When i call one of the WSDL operation from a spring project, i am getting following exception -
com.sun.istack.internal.SAXException2: unable to marshal type "com.pkg.wsdl.ABC" as an element because it is missing an @XmlRootElement annotation
I am…
chappalprasad
- 775
- 4
- 15
- 26
4
votes
2 answers
Rename serializable class
If i Serializable the following code using XmlSerializer.
[XmlRoot("products")]
public class Products : List
{
}
public class Product
{
}
I get the following xml
How to i write to get the…
Andreas
- 451
- 1
- 4
- 3
3
votes
1 answer
Add Attribute to XMLROOT ElementName
I have a class with the class attribute :
[XmlRoot(ElementName = "RootXML")]
public class Apply
{
/My Properties
}
now to create an xml from the above class I use below function :
public virtual string RenderXml()
{
XmlTextWriter writer =…
Zaki
- 5,540
- 7
- 54
- 91
2
votes
3 answers
XmlRoot attribute is needed to deserialize but in xml file there is no root attribute
I have a question: I have an .xml file
-
2
Live Test Event
6
Test tournament
…
Oleg Kopot
- 23
- 3
2
votes
1 answer
JaxB unmarshall unexpected element error
I am running jaxb on the following xml file.
bear
Using the following java code.
import java.io.File;
import javax.xml.bind.JAXBContext;
import…
jgr208
- 2,896
- 9
- 36
- 64
1
vote
1 answer
1
vote
4 answers
I have @xmlrootelement , but keep getting this exception: unable to marshal type as an element because it is missing an @XmlRootElement
I am trying to marshall/unmarshall a class which does not have @xmlrootelement. Can anyone help ? The marshaller I am using is of type Jaxb2Marshaller of the Spring's org.springframework.oxm.jaxb Most of the solutions present are of type…
Santosh Ravi Teja
- 247
- 1
- 7
- 18
1
vote
1 answer
Serializing class decorated with XmlRoot, error when used in List
When i try to serialize a class element of type Test, it gives an xml with root element as "testing" which is set using XmlRoot.
But when I try to serialize an element of class Elems, Test element is serialized with root element "Test" instead of…
Rozuur
- 4,115
- 25
- 31
1
vote
1 answer
Nested FOR XML results with SQL Server
My MS SQL table has following data
ID CONTENT UDH TO FROM
-------------------------------------------
1 HELLO 1 9812 22
2 HELLO 1 9813 22
3 HELLO 1 9814 …
Rizwan Shaikh
- 95
- 7
1
vote
1 answer
How to print pretty JSON using docx4j into a word document?
I want to print a simple pretty json string (containing multiple line breaks - many \n) into a word document. I tried the following but docx4j just prints all the contents inline in one single line (without \n). Ideally it should print multiline…
Dhwanit
- 610
- 1
- 9
- 17
1
vote
1 answer
XmlRoot attribute serialization to a file
I have the following code serializing an object into a file:
TemplateClass item = new TemplateClass();
// Fill in item
XmlSerializer writer = new XmlSerializer(typeof(TemplateClass));
using (StreamWriter file = new StreamWriter(filePath))
{
…
Romonov
- 8,145
- 14
- 43
- 55
1
vote
0 answers
Take off XmlRootElement
I´m making a request. I should return a String.
My Answer should be:
1
My atually answer is this:
1
Goldbones
- 1,407
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