Use this tag for questions specific to XML Path Language (XPath) version 3.0
W3C Recommendations:
Resources:
Online Training
A"The Evolution of XPath: What’s New in XPath 3.0" -- A Pluralsight video-course (4.5h), by Dimitre Novatchev
Questions tagged [xpath-3.0]
47 questions
4
votes
1 answer
Can a function defined by xsl:function substitute for an xpath 3.0 inline function?
I was playing with this example in the xpath 3.0 spec:
fn:fold-left(function($a, $b) { $a + $b }, 0, 1 to 5)
I tried to substitute the inline function with a function defined by xsl:function.
Fred Finkle
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4
votes
2 answers
XPath 3.0: select nodes by condition (find max child nodes by date)
Given XML:
lospejos
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4
votes
1 answer
Iterate over nodes containing CDATA and concatenate them and how to retrieve specific data of the concatenate data
I'm new to XSLT and need to solve a nasty problem and I've no change to solve it.
The following example describes my problem:
XXX 123456123]]>
Dirk
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3
votes
1 answer
Any XPath/XSLT/XQuery 3.0 specific learning resources out there?
I'd prefer books. Do you know of any due to be released? Work ongoing?
I ask as I want to get up to speed with the new features in 3.0 (I know its not finalized yet), but I can't seem to find much. I know I could ref the ongoing spec but if that…
Dino Fancellu
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3
votes
3 answers
Parsing a URL query string into a map of parameters with XPath
What would be the most readable way to parse a URL query string into a { 'param': 'value' } map in XSLT/XPath 3.0?
Note: this is the inverse function of the one described in Building a URL query string from a map of parameters with XPath.
Update: I…
Martynas Jusevičius
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3
votes
3 answers
Building a URL query string from a map of parameters with XPath
What would be the most readable way to build a URL query string from a { 'param': 'value' } map in XSLT/XPath 3.0?
Martynas Jusevičius
- 575
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3
votes
1 answer
xslt: whats the easiest way to do a negated selection?
Basically what I would like is something like this that finds all nodes where the ID cannot be lookup'ed up ('broken links') :
darune
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3
votes
1 answer
XPath 3.x - sort function
I need to sort a sequence of elements using plain XPath 3.0, so no XQuery, no XSL-T and no code. I tried following this answer on how to use the sort function, but I'm not an expert in XPath, so I couldn't figure out how to use it.
So, my document…
Lukas
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3
votes
1 answer
XPath: Why does /document-node() match the document node?
An XPath expression of / returns the document node.
An XPath expression of /html is equivalent to /child::html and given an HTML document would return the html element. This is of course evaluated by going to the document node (indicated by the /)…
VKK
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3
votes
1 answer
Xquery Node returns HTML code and browser don't read it
I have a XML code looking like this:
<div style="text-align: justify;">El Casino de Asturias alberga una sala polivalente para cualquier tipo de acto desde conferencias, convenciones o reuniones de trabajo, hasta…
Santanor
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2
votes
3 answers
How to do a case insensitive lookup over a set of nodes in XSLT/XPATH?
Say I have this data:
toddmo
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2
votes
2 answers
XPath 3.0 Recursive Query
I have some XML data with an inheritance-like semantics, and I'd like to make a query that takes the inheritance into consideration. I know it is not possible in XPath 1.0, but I believe it is possible in XPath 3.0, but I'm not familiar with 3.0.
So…
Daniel C. Sobral
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2
votes
2 answers
XPath 3.0 Serialize without Namespaces in Scope
While answering this question, it occurred to me that I know how to use the XSLT 3.0 (XPath 3.0) serialize() function, but that I do not know how to avoid serialization of namespaces that are in scope. Here is a minimal example:
XML Input
Mathias Müller
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2
votes
2 answers
What does ! mean in XPath 3.0?
XPath 3.0 defines a new operator called the 'mapping operator'. It is denoted by the exclamation mark --!.
What does A!B mean? How do we use the ! operator? Could someone give me an example?
Chong Lip Phang
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2
votes
2 answers
Construct an alphabetical sequence
This XPath expression:
for $n in 1 to 5 return $n
Returns
1 2 3 4 5
Is it possible to do something similar with alphabetic characters?
Severin Foreman
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