How to send an email with Gmail as provider using Python?

Question

I am trying to send email (Gmail) using python, but I am getting following error.

Traceback (most recent call last):  
File "emailSend.py", line 14, in <module>  
server.login(username,password)  
File "/usr/lib/python2.5/smtplib.py", line 554, in login  
raise SMTPException("SMTP AUTH extension not supported by server.")  
smtplib.SMTPException: SMTP AUTH extension not supported by server.

The Python script is the following.

import smtplib

fromaddr = 'user_me@gmail.com'
toaddrs  = 'user_you@gmail.com'
msg = 'Why,Oh why!'
username = 'user_me@gmail.com'
password = 'pwd'
server = smtplib.SMTP('smtp.gmail.com:587')
server.starttls()
server.login(username,password)
server.sendmail(fromaddr, toaddrs, msg)
server.quit()

Answer 1

def send_email(user, pwd, recipient, subject, body):
    import smtplib

    FROM = user
    TO = recipient if isinstance(recipient, list) else [recipient]
    SUBJECT = subject
    TEXT = body

    # Prepare actual message
    message = """From: %s\nTo: %s\nSubject: %s\n\n%s
    """ % (FROM, ", ".join(TO), SUBJECT, TEXT)
    try:
        server = smtplib.SMTP("smtp.gmail.com", 587)
        server.ehlo()
        server.starttls()
        server.login(user, pwd)
        server.sendmail(FROM, TO, message)
        server.close()
        print 'successfully sent the mail'
    except:
        print "failed to send mail"

if you want to use Port 465 you have to create an SMTP_SSL object:

# SMTP_SSL Example
server_ssl = smtplib.SMTP_SSL("smtp.gmail.com", 465)
server_ssl.ehlo() # optional, called by login()
server_ssl.login(gmail_user, gmail_pwd)  
# ssl server doesn't support or need tls, so don't call server_ssl.starttls() 
server_ssl.sendmail(FROM, TO, message)
#server_ssl.quit()
server_ssl.close()
print 'successfully sent the mail'

Answer 2

You need to say EHLO before just running straight into STARTTLS:

server = smtplib.SMTP('smtp.gmail.com:587')
server.ehlo()
server.starttls()

---

Also you should really create From:, To: and Subject: message headers, separated from the message body by a blank line and use CRLF as EOL markers.

E.g.

msg = "\r\n".join([
  "From: user_me@gmail.com",
  "To: user_you@gmail.com",
  "Subject: Just a message",
  "",
  "Why, oh why"
  ])

Note:

In order for this to work you need to enable "Allow less secure apps" option in your gmail account configuration. Otherwise you will get a "critical security alert" when gmail detects that a non-Google apps is trying to login your account.

Answer 3

I ran into a similar problem and stumbled on this question. I got an SMTP Authentication Error but my user name / pass was correct. Here is what fixed it. I read this:

https://support.google.com/accounts/answer/6010255

In a nutshell, google is not allowing you to log in via smtplib because it has flagged this sort of login as "less secure", so what you have to do is go to this link while you're logged in to your google account, and allow the access:

https://www.google.com/settings/security/lesssecureapps

Once that is set (see my screenshot below), it should work.

Login now works:

smtpserver = smtplib.SMTP("smtp.gmail.com", 587)
smtpserver.ehlo()
smtpserver.starttls()
smtpserver.ehlo()
smtpserver.login('me@gmail.com', 'me_pass')

Response after change:

(235, '2.7.0 Accepted')

Response prior:

smtplib.SMTPAuthenticationError: (535, '5.7.8 Username and Password not accepted. Learn more at\n5.7.8 http://support.google.com/mail/bin/answer.py?answer=14257 g66sm2224117qgf.37 - gsmtp')

Still not working? If you still get the SMTPAuthenticationError but now the code is 534, its because the location is unknown. Follow this link:

https://accounts.google.com/DisplayUnlockCaptcha

Click continue and this should give you 10 minutes for registering your new app. So proceed to doing another login attempt now and it should work.

UPDATE: This doesn't seem to work right away you may be stuck for a while getting this error in smptlib:

235 == 'Authentication successful'
503 == 'Error: already authenticated'

The message says to use the browser to sign in:

SMTPAuthenticationError: (534, '5.7.9 Please log in with your web browser and then try again. Learn more at\n5.7.9 https://support.google.com/mail/bin/answer.py?answer=78754 qo11sm4014232igb.17 - gsmtp')

After enabling 'lesssecureapps', go for a coffee, come back, and try the 'DisplayUnlockCaptcha' link again. From user experience, it may take up to an hour for the change to kick in. Then try the sign-in process again.

You many now also need create an app password by following the steps under section "Create & use app passwords" here: support.google.com/accounts/answer/185833

Answer 4

This Works

Create Gmail APP Password!

After you create that then create a file called sendgmail.py

Then add this code:

#!/usr/bin/env python3
# -*- coding: utf-8 -*-
# =============================================================================
# Created By  : Jeromie Kirchoff
# Created Date: Mon Aug 02 17:46:00 PDT 2018
# =============================================================================
# Imports
# =============================================================================
import smtplib

# =============================================================================
# SET EMAIL LOGIN REQUIREMENTS
# =============================================================================
gmail_user = 'THEFROM@gmail.com'
gmail_app_password = 'YOUR-GOOGLE-APPLICATION-PASSWORD!!!!'

# =============================================================================
# SET THE INFO ABOUT THE SAID EMAIL
# =============================================================================
sent_from = gmail_user
sent_to = ['THE-TO@gmail.com', 'THE-TO@gmail.com']
sent_subject = "Hey Friends!"
sent_body = ("Hey, what's up? friend!\n\n"
             "I hope you have been well!\n"
             "\n"
             "Cheers,\n"
             "Jay\n")

email_text = """\
From: %s
To: %s
Subject: %s

%s
""" % (sent_from, ", ".join(sent_to), sent_subject, sent_body)

# =============================================================================
# SEND EMAIL OR DIE TRYING!!!
# Details: http://www.samlogic.net/articles/smtp-commands-reference.htm
# =============================================================================

try:
    server = smtplib.SMTP_SSL('smtp.gmail.com', 465)
    server.ehlo()
    server.login(gmail_user, gmail_app_password)
    server.sendmail(sent_from, sent_to, email_text)
    server.close()

    print('Email sent!')
except Exception as exception:
    print("Error: %s!\n\n" % exception)

So, if you are successful, will see an image like this:

I tested by sending an email from and to myself.

Note: I have 2-Step Verification enabled on my account. App Password works with this! (for gmail smtp setup, you must go to https://support.google.com/accounts/answer/185833?hl=en and follow the below steps)

This setting is not available for accounts with 2-Step Verification enabled. Such accounts require an application-specific password for less secure apps access.

Clarification

Navigate to https://myaccount.google.com/apppasswords and create an APP Password as stated above.

Answer 5

Here is a Gmail API example. Although more complicated, this is the only method I found that works in 2019. This example was taken and modified from:

https://developers.google.com/gmail/api/guides/sending

You'll need create a project with Google's API interfaces through their website. Next you'll need to enable the GMAIL API for your app. Create credentials and then download those creds, save it as credentials.json.

import pickle
import os.path
from googleapiclient.discovery import build
from google_auth_oauthlib.flow import InstalledAppFlow
from google.auth.transport.requests import Request

from email.mime.text import MIMEText
import base64

#pip install --upgrade google-api-python-client google-auth-httplib2 google-auth-oauthlib

# If modifying these scopes, delete the file token.pickle.
SCOPES = ['https://www.googleapis.com/auth/gmail.readonly', 'https://www.googleapis.com/auth/gmail.send']

def create_message(sender, to, subject, msg):
    message = MIMEText(msg)
    message['to'] = to
    message['from'] = sender
    message['subject'] = subject

    # Base 64 encode
    b64_bytes = base64.urlsafe_b64encode(message.as_bytes())
    b64_string = b64_bytes.decode()
    return {'raw': b64_string}
    #return {'raw': base64.urlsafe_b64encode(message.as_string())}

def send_message(service, user_id, message):
    #try:
    message = (service.users().messages().send(userId=user_id, body=message).execute())
    print( 'Message Id: %s' % message['id'] )
    return message
    #except errors.HttpError, error:print( 'An error occurred: %s' % error )

def main():
    """Shows basic usage of the Gmail API.
    Lists the user's Gmail labels.
    """
    creds = None
    # The file token.pickle stores the user's access and refresh tokens, and is
    # created automatically when the authorization flow completes for the first
    # time.
    if os.path.exists('token.pickle'):
        with open('token.pickle', 'rb') as token:
            creds = pickle.load(token)
    # If there are no (valid) credentials available, let the user log in.
    if not creds or not creds.valid:
        if creds and creds.expired and creds.refresh_token:
            creds.refresh(Request())
        else:
            flow = InstalledAppFlow.from_client_secrets_file(
                'credentials.json', SCOPES)
            creds = flow.run_local_server(port=0)
        # Save the credentials for the next run
        with open('token.pickle', 'wb') as token:
            pickle.dump(creds, token)

    service = build('gmail', 'v1', credentials=creds)

    # Example read operation
    results = service.users().labels().list(userId='me').execute()
    labels = results.get('labels', [])

    if not labels:
        print('No labels found.')
    else:
        print('Labels:')
    for label in labels:
        print(label['name'])

    # Example write
    msg = create_message("from@gmail.com", "to@gmail.com", "Subject", "Msg")
    send_message( service, 'me', msg)

if __name__ == '__main__':
    main()

Answer 6

You down with OOP?

#!/usr/bin/env python


import smtplib

class Gmail(object):
    def __init__(self, email, password):
        self.email = email
        self.password = password
        self.server = 'smtp.gmail.com'
        self.port = 587
        session = smtplib.SMTP(self.server, self.port)        
        session.ehlo()
        session.starttls()
        session.ehlo
        session.login(self.email, self.password)
        self.session = session

    def send_message(self, subject, body):
        ''' This must be removed '''
        headers = [
            "From: " + self.email,
            "Subject: " + subject,
            "To: " + self.email,
            "MIME-Version: 1.0",
           "Content-Type: text/html"]
        headers = "\r\n".join(headers)
        self.session.sendmail(
            self.email,
            self.email,
            headers + "\r\n\r\n" + body)


gm = Gmail('Your Email', 'Password')

gm.send_message('Subject', 'Message')

Answer 7

You can find it here: http://jayrambhia.com/blog/send-emails-using-python

smtp_host = 'smtp.gmail.com'
smtp_port = 587
server = smtplib.SMTP()
server.connect(smtp_host,smtp_port)
server.ehlo()
server.starttls()
server.login(user,passw)
fromaddr = raw_input('Send mail by the name of: ')
tolist = raw_input('To: ').split()
sub = raw_input('Subject: ')

msg = email.MIMEMultipart.MIMEMultipart()
msg['From'] = fromaddr
msg['To'] = email.Utils.COMMASPACE.join(tolist)
msg['Subject'] = sub  
msg.attach(MIMEText(raw_input('Body: ')))
msg.attach(MIMEText('\nsent via python', 'plain'))
server.sendmail(user,tolist,msg.as_string())

Answer 8

Not directly related but still worth pointing out is that my package tries to make sending gmail messages really quick and painless. It also tries to maintain a list of errors and tries to point to the solution immediately.

It would literally only need this code to do exactly what you wrote:

import yagmail
yag = yagmail.SMTP('user_me@gmail.com')
yag.send('user_you@gmail.com', 'Why,Oh why!')

Or a one liner:

yagmail.SMTP('user_me@gmail.com').send('user_you@gmail.com', 'Why,Oh why!')

For the package/installation please look at git or pip, available for both Python 2 and 3.

Answer 9

Dec, 2022 Update:

You need to use an app password to allow your app to access your google account.

Sign in with App Passwords:

An App Password is a 16-digit passcode that gives a less secure app or device permission to access your Google Account. App Passwords can only be used with accounts that have 2-Step Verification turned on.

In addition, google hasn't allowed your app to access your google account with username(email address) and password since May 30, 2022. So now, you need username(email address) and an app password to access your google account.

Less secure apps & your Google Account:

To help keep your account secure, from May 30, 2022, ​​Google no longer supports the use of third-party apps or devices which ask you to sign in to your Google Account using only your username and password.

How to generate an app password:

First, click on Account from 9 dots:

Then, click on App passwords from Security. *Don't forget to turn on 2-Step Verification before generating an app password otherwise you cannot generate an app password:

Then, click on Other (Custom name):

Then, put your app name, then click on GENERATE:

Finally, you could generate the app password xylnudjdiwpojwzm:

So, your code with the app password above is as shown below:

import smtplib

fromaddr = 'user_me@gmail.com'
toaddrs  = 'user_you@gmail.com'
msg = 'Why,Oh why!'
username = 'user_me@gmail.com'
password = 'xylnudjdiwpojwzm' # Here
server = smtplib.SMTP('smtp.gmail.com:587')
server.starttls()
server.login(username,password)
server.sendmail(fromaddr, toaddrs, msg)
server.quit()

In addition, settings.py with the app password above in Django is as shown below:

# "settings.py"

EMAIL_BACKEND = 'django.core.mail.backends.smtp.EmailBackend'
EMAIL_HOST = 'smtp.gmail.com'
EMAIL_PORT = 587
EMAIL_USE_TLS = True
EMAIL_HOST_USER = 'myaccount@gmail.com'
EMAIL_HOST_PASSWORD = 'xylnudjdiwpojwzm' # Here

Answer 10

Realized how painful many of the things are with sending emails via Python thus I made an extensive library for it. It also has Gmail pre-configured (so you don't have to remember Gmail's host and port):

from redmail import gmail
gmail.user_name = "you@gmail.com"
gmail.password = "<YOUR APPLICATION PASSWORD>"

# Send an email
gmail.send(
    subject="An example email",
    receivers=["recipient@example.com"],
    text="Hi, this is text body.",
    html="<h1>Hi, this is HTML body.</h1>"
)

Of course you need to configure your Gmail account (don't worry, it's simple):

1. Set up 2-step-verification (if not yet set up)
2. Create an Application password
3. Put the Application password to the gmail object and done!

Red Mail is actually pretty extensive (include attachments, embed images, send with cc and bcc, template with Jinja etc.) and should hopefully be all you need from an email sender. It is also well tested and documented. I hope you find it useful.

To install:

pip install redmail

Documentation: https://red-mail.readthedocs.io/en/latest/

Source code: https://github.com/Miksus/red-mail

Note that Gmail don't allow changing the sender. The sender address is always you.

Answer 11

Enable less secure apps on your gmail account and use (Python>=3.6):

import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText

gmailUser = 'XXXXX@gmail.com'
gmailPassword = 'XXXXX'
recipient = 'XXXXX@gmail.com'

message = f"""
Type your message here...
"""

msg = MIMEMultipart()
msg['From'] = f'"Your Name" <{gmailUser}>'
msg['To'] = recipient
msg['Subject'] = "Subject here..."
msg.attach(MIMEText(message))

try:
    mailServer = smtplib.SMTP('smtp.gmail.com', 587)
    mailServer.ehlo()
    mailServer.starttls()
    mailServer.ehlo()
    mailServer.login(gmailUser, gmailPassword)
    mailServer.sendmail(gmailUser, recipient, msg.as_string())
    mailServer.close()
    print ('Email sent!')
except:
    print ('Something went wrong...')

Answer 12

There is a gmail API now, which lets you send email, read email and create drafts via REST. Unlike the SMTP calls, it is non-blocking which can be a good thing for thread-based webservers sending email in the request thread (like python webservers). The API is also quite powerful.

• Of course, email should be handed off to a non-webserver queue, but it's nice to have options.

It's easiest to setup if you have Google Apps administrator rights on the domain, because then you can give blanket permission to your client. Otherwise you have to fiddle with OAuth authentication and permission.

Here is a gist demonstrating it:

https://gist.github.com/timrichardson/1154e29174926e462b7a

Answer 13

great answer from @David, here is for Python 3 without the generic try-except:

def send_email(user, password, recipient, subject, body):

    gmail_user = user
    gmail_pwd = password
    FROM = user
    TO = recipient if type(recipient) is list else [recipient]
    SUBJECT = subject
    TEXT = body

    # Prepare actual message
    message = """From: %s\nTo: %s\nSubject: %s\n\n%s
    """ % (FROM, ", ".join(TO), SUBJECT, TEXT)

    server = smtplib.SMTP("smtp.gmail.com", 587)
    server.ehlo()
    server.starttls()
    server.login(gmail_user, gmail_pwd)
    server.sendmail(FROM, TO, message)
    server.close()

Answer 14

Seems like problem of the old smtplib. In python2.7 everything works fine.

Update: Yep, server.ehlo() also could help.

Answer 15

---

This will help you. I use this method

---

1. First of all, you must activate "2-step verification" from your Google account. follow the below path:

go to google account -> "security" tab (from left menu) -> find "How you sign in to Google" and then enable "2-step verification"

2. click on "2-step verification" and then click on "App passwords" at the bottom of the page. Then, click on "select app" and chose "other (custom name)". Then, write a name and click on generate.

3. save the password which displays on the screen.

4. I used below code, you can confiq and use it.

import os
from email.message import EmailMessage
import ssl
import smtplib
email_sender = 'mohsennavazani@gmail.com' #only gmail
email_password = 'Your password from section 3'
email_receiver = 'mohsennavazani@gmail.com' #any type of email

subject = 'check my website (Mohsennavazani.ir)'

body = """
Hello,
this is a test 

"""

em = EmailMessage()
em['From'] = email_sender
em['To'] =  email_receiver
em['Subject'] = subject
em.set_content(body)

#add a layer of security
context = ssl.create_default_context()

#sending the email
with smtplib.SMTP_SSL('smtp.gmail.com', 465, context=context) as smtp: 
    smtp.login(email_sender,email_password)
    smtp.sendmail(email_sender,email_receiver, em.as_string())

5- (optional) if you need to send an email to more that 1 email address, you can use the below code in the last part.

li = ["mohsennavazani@gmail.com", "sbu.ar.mohsen@gmail.com"] 
with smtplib.SMTP_SSL('smtp.gmail.com',465,context=context) as smtp: 
    smtp.login(email_sender,email_password)
    smtp.sendmail(email_sender,li, em.as_string())

Answer 16

    import smtplib

    fromadd='from@gmail.com'
    toadd='send@gmail.com'

    msg='''hi,how r u'''
    username='abc@gmail.com'
    passwd='password'

    try:
        server = smtplib.SMTP('smtp.gmail.com:587')
        server.ehlo()
        server.starttls()
        server.login(username,passwd)

        server.sendmail(fromadd,toadd,msg)
        print("Mail Send Successfully")
        server.quit()

   except:
        print("Error:unable to send mail")

   NOTE:https://www.google.com/settings/security/lesssecureapps that                                                         should be enabled

Answer 17

import smtplib
server = smtplib.SMTP('smtp.gmail.com', 587)
server.ehlo()
server.starttls()
server.login("fromaddress", "password")
msg = "HI!"
server.sendmail("fromaddress", "receiveraddress", msg)
server.quit()