Trying to send email from python

Question

i am new to python, when am trying to sending mail by using python my program is bellow

import smtplib
from smtplib import SMTP

sender = 'raju.ab@gmail.com'
receivers = ['sudeer.p@eunoia.in']

message = """ this message sending from python
for testing purpose
"""

try:
smtpObj = smtplib.SMTP('smtp.gmail.com', 587)
smtpObj.ehlo()
smtpObj.starttls()
smtpObj.ehlo()
smtpObj.login(username,password)
smtpObj.sendmail(sender, receivers, message)
smtpObj.quit()
print "Successfully sent email"
except smtplib.SMTPException:

print "Error: unable to send email"

when i execute it shows Error: unable to send mail message, how to send email in python please explain

*"it shows Error: unable to send mail message"* - that's exactly what you've asked it to do! If you didn't wrap the whole process in a `try`, you would get a more specific error message that gave you more information about the problem. — jonrsharpe, Dec 03 '14 at 13:01

score 2 · Answer 1 · edited May 23 '17 at 12:23

as is said here: How to send an email with Gmail as provider using Python?

This code works. But GMAIL wil warn you if you want to allow this script send the email or not. Sign in in your account, and accesss this URL: https://www.google.com/settings/security/lesssecureapps

import smtplib
gmail_user = "yourmail@gmail.com"
gmail_pwd = "mypassword"
FROM = 'yourmail@gmail.com'
TO = ['receiber@email.com'] #must be a list
SUBJECT = "Testing sending using gmail"
TEXT = "Testing sending mail using gmail servers"
# Prepare actual message
message = """\From: %s\nTo: %s\nSubject: %s\n\n%s
""" % (FROM, ", ".join(TO), SUBJECT, TEXT)
try:
  #server = smtplib.SMTP(SERVER) 
  server = smtplib.SMTP("smtp.gmail.com", 587) #or port 465 doesn't seem to work!
  server.ehlo()
  server.starttls()
  server.login(gmail_user, gmail_pwd)
  server.sendmail(FROM, TO, message)
  #server.quit()
  server.close()
  print 'successfully sent the mail'
except:
  print "failed to send mail"

Thanks for the information about the warning. The URL information worked for me. — BaldDude, Dec 04 '14 at 13:20

score 2 · Accepted Answer · answered Dec 03 '14 at 13:40

2

What i have done in code :

1.Added a error object to get the error message

import smtplib
from smtplib import SMTP       

try:
    sender = 'xxx@gmail.com'
    receivers = ['xxx.com']

    message = """ this message sending from python
    for testing purpose
    """
    smtpObj = smtplib.SMTP(host='smtp.gmail.com', port=587)
    smtpObj.ehlo()
    smtpObj.starttls()
    smtpObj.ehlo()
    smtpObj.login('xxx','xxx')
    smtpObj.sendmail(sender, receivers, message)
    smtpObj.quit()
    print "Successfully sent email"
except smtplib.SMTPException,error:
    print str(error)
    print "Error: unable to send email"

If u ran this code u would see a error message like this stating that google is not allowing u to login via code

Things to change in gmail:

1.Login to gmail

2.Go to this link https://www.google.com/settings/security/lesssecureapps

3.Click enable then retry the code

Hopes it help :)

But there are security threats if u enable it

answered Dec 03 '14 at 13:40

The6thSense

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I get invalid syntax at except line, pointing at the comma before error (line 20 in your code). Why? – Yannis Dran Dec 13 '16 at 00:19
@YannisDran are you using python 3 – The6thSense Dec 15 '16 at 06:25
@YannisDran could you show the sample code and except syntax is different in python 3 – The6thSense Dec 15 '16 at 08:11
as soon as I go home, I ll post it to you. – Yannis Dran Dec 15 '16 at 08:16
1

For Python 2.6 and later and Python 3.x: except Exception as e: print(e) – paraS elixiR Nov 14 '19 at 07:28

Trying to send email from python

2 Answers2