I'm looking for a function to arrange some elements around a circle.
result should be something like :
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ThiefMaster
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Omid
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13@camus my real problem is that i don't know trigonometry ;) – Omid Apr 14 '12 at 09:12
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only for 4 elements or for `n` elements in same distance? – Neysor Apr 14 '12 at 09:13
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@Neysor `n` element with different distance. – Omid Apr 14 '12 at 09:15
5 Answers
86
Here's some code that should help you:
var numElements = 4,
angle = 0
step = (2*Math.PI) / numElements;
for(var i = 0; i < numElements.length; i++) {
var x = container_width/2 + radius * Math.cos(angle);
var y = container_height/2 + radius * Math.sin(angle);
angle += step;
}
It is not complete but should give you a good start.
Update: Here's something that actually works:
var radius = 200; // radius of the circle
var fields = $('.field'),
container = $('#container'),
width = container.width(),
height = container.height(),
angle = 0,
step = (2*Math.PI) / fields.length;
fields.each(function() {
var x = Math.round(width/2 + radius * Math.cos(angle) - $(this).width()/2),
y = Math.round(height/2 + radius * Math.sin(angle) - $(this).height()/2);
$(this).css({
left: x + 'px',
top: y + 'px'
});
angle += step;
});
Demo: http://jsfiddle.net/ThiefMaster/LPh33/
Here's an improved version where you can change the element count.

ThiefMaster
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You need to add the circle's coordinates, and subtract half of the element's dimensions, from `x` and `y` yourself. – Delan Azabani Apr 14 '12 at 09:23
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@ThiefMaster That's Ok friend, just i don't want to use relative positioning. how to do that if `fields` and `cycle` are not in the same container – Omid Apr 14 '12 at 09:36
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1I really want to learn about this. Could you please some explanation with mathematical formula on your answer. Pretty Please :) – Starx Sep 28 '12 at 08:06
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1
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2@ThiefMaster, Common a diamond after your name and you are still greedy?? :P – Starx Sep 28 '12 at 15:24
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This is great but does the variable "angle" hold an angular measurement? Doesn't it instead hold a value expressed radians? – NShiell Apr 04 '22 at 13:50
15
For an element around a centre at (x, y), distance r, the element's centre should be positioned at:
(x + r cos(2kπ/n), y + r sin(2kπ/n))
where n is the number of elements, and k is the "number" of the element you're currently positioning (between 1 and n inclusive).

ThiefMaster
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Delan Azabani
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6
I've combined ThiefMaster's fiddle with the jQuery pointAt plugin:
Demo: http://jsfiddle.net/BananaAcid/nytN6/
the code is somewhat like above.
might be interesting to some of you.

BananaAcid
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1
Arrange Elements In Circle (Javascript)
function arrangeElementsInCircle (elements, x, y, r) {
for (var i = 0; i < elements.length; i++) {
elements[i].scaleX = 1 / elements.length
elements[i].scaleY = 1 / elements.length
elements[i].x = (x + r * Math.cos((2 * Math.PI) * i/elements.length))
elements[i].y = (y + r * Math.sin((2 * Math.PI) * i/store.length))
}
}
Where x,y
is point co-ordinates and elements
is array of elements to be placed and r
is radius.

Amit Kumar Khare
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0
Javascript only version of thiefmaster's answer
function distributeFields(deg){
deg = deg || 0;
var radius = 200;
var fields = document.querySelectorAll('.field'), //using queryselector instead of $ to select items
container = document.querySelector('#container'),
width = container.offsetWidth, //offsetWidth gives the width of the container
height = container.offsetHeight,
angle = deg || Math.PI * 3.5,
step = (2 * Math.PI) / fields.length;
console.log(width, height)
//using forEach loop on a NodeList instead of a Jquery .each,
//so we can now use "field" as an iterator instead of $(this)
fields.forEach((field)=>{
var x = Math.round(width / 2 + radius * Math.cos(angle) - field.offsetWidth/2);
var y = Math.round(height / 2 + radius * Math.sin(angle) - field.offsetHeight/2);
console.log(x, y)
field.style.left = x + 'px'; //adding inline style to the document (field)
field.style.top= y + 'px';
angle += step;
})
}
distributeFields();

k1st
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