How to implement exit button behaviour?

Question

In my application, i have exit button to exit from the application. So i have finish() all the activities. But i loses h/w back button behaviour. So my question is: I want to go back to all activites and also want to exit when clicking on exit button..

possible duplicate of [Close application?](http://stackoverflow.com/questions/2042222/close-application) — Dharmendra, Apr 18 '12 at 09:01

score 4 · Accepted Answer · edited May 23 '17 at 12:03

4

your question is little bit confusing but i think you need this

Finish all activities when back button is pressed

and never use system.exit for exiting application Close application and launch home screen on Android

edited

editButton.setOnClickListener(new View.OnCLickListener()
{
       public void onClick(View v) {
        finish();
        Intent intent = new Intent(Intent.ACTION_MAIN); 
        intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP); 
        intent.addCategory(Intent.CATEGORY_HOME); 
        startActivity(intent);

       }
});

edited May 23 '17 at 12:03

Community

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1

answered Apr 18 '12 at 08:57

vipin

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Nope..I want to back all activites but when clicking on exit it should exit the app.. – dreamcoder Apr 18 '12 at 09:00
will application exit on clicking exit button? as you are recreating intent? – dreamcoder Apr 18 '12 at 09:13
yes it will take you out from application and also clear your activity stack because in it we have added flag FLAG_ACTIVITY_CLEAR_TOP – vipin Apr 18 '12 at 09:16

score 0 · Answer 2 · edited May 23 '17 at 12:03

0

System.exit(1)

may help.. arguement is important.. you can also try this approach..

edited May 23 '17 at 12:03

Community

1
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answered Apr 18 '12 at 08:47

ngesh

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score 0 · Answer 3 · answered Apr 18 '12 at 08:52

0

you may want to override onBackPressed() method and call finish() inside it

answered Apr 18 '12 at 08:52

julian

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No..it will still come out of application.. i want to move to back page and also want to exit from application when i click on exit button.. – dreamcoder Apr 18 '12 at 08:58
Can you please describe the scenario? I don't get the question either, sorry for that. – julian Apr 18 '12 at 09:09

score 0 · Answer 4 · answered Apr 18 '12 at 09:04

Use below code ...I hope it work

ActivityManager am = (ActivityManager) this.getSystemService(ACTIVITY_SERVICE);
    List<ActivityManager.RunningTaskInfo> taskInfo = am.getRunningTasks(1); 
    ComponentName componentInfo = taskInfo.get(0).topActivity;
    am.restartPackage(componentInfo.getPackageName());

score 0 · Answer 5 · edited Jul 03 '17 at 19:23

/**easiest way that I found and working. Setting up onclick="exitBtn" for button in XML file. and defining that button in java*/

public void exitBtn(View v) {

    AlertDialog.Builder builder = new AlertDialog.Builder(OderActivity.this); // this will pop up a dialog box for OK or Cancel//
    builder.setMessage("Do you want to exit");
    builder.setCancelable(true);
    builder.setPositiveButton("Ok", new DialogInterface.OnClickListener() {
        @Override
        public void onClick(DialogInterface dialogInterface, int i) {
            Intent intent = new Intent(Intent.ACTION_MAIN);
            intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
            intent.addCategory(Intent.CATEGORY_HOME);
            startActivity(intent);
            finish();

        }
    });
    builder.setNegativeButton("Cancel", new DialogInterface.OnClickListener() {
        @Override
        public void onClick(DialogInterface dialogInterface, int i) {
            dialogInterface.cancel();
        }
    });

    AlertDialog alert = builder.create();
    alert.show();
}

if u don't want to include the dialog box, then u can remove all the alert dialog codes and simply put from intent to finish() lines from the above code. — Freaky NT, Jul 03 '17 at 19:18

How to implement exit button behaviour?

5 Answers5

edited