250

I have a String with an unknown length that looks something like this

"dog, cat, bear, elephant, ..., giraffe"

What would be the optimal way to divide this string at the commas so each word could become an element of an ArrayList?

For example

List<String> strings = new ArrayList<Strings>();
// Add the data here so strings.get(0) would be equal to "dog",
// strings.get(1) would be equal to "cat" and so forth.
Jonik
  • 80,077
  • 70
  • 264
  • 372
James Fazio
  • 6,370
  • 9
  • 38
  • 47

16 Answers16

403

You could do this:

String str = "...";
List<String> elephantList = Arrays.asList(str.split(","));

Basically the .split() method will split the string according to (in this case) delimiter you are passing and will return an array of strings.

However, you seem to be after a List of Strings rather than an array, so the array must be turned into a list by using the Arrays.asList() utility. Just as an FYI you could also do something like so:

String str = "...";
ArrayList<String> elephantList = new ArrayList<>(Arrays.asList(str.split(","));

But it is usually better practice to program to an interface rather than to an actual concrete implementation, so I would recommend the 1st option.

olajide
  • 972
  • 1
  • 13
  • 26
npinti
  • 51,780
  • 5
  • 72
  • 96
  • @JamesFazio: The `.split` method is one of the most handy methods in the String class, I would recommend you check out the link for the JavaDocs I have included in my answer ;). – npinti May 17 '12 at 07:52
  • 10
    Keep in mind this won't trim the values so strings.get(1) will be " cat" not "cat" – Alb Jun 28 '13 at 15:33
  • 52
    `str.split` accepts regex so you can use `str.split(",[ ]*");` so you remove commas and spaces after commas. – vertti Oct 31 '13 at 08:38
  • 5
    A comma delimited file (csv) might have a a comma in quotes, meaning it's not a delimiter. In this case Split will not work. – Steven Trigg Mar 08 '14 at 02:35
  • 2
    The second option requires as cast to `ArrayList`. – C_B Aug 28 '14 at 09:57
  • 3
    If you need to keep empty entries (eg.for consistent array length) use split(",",-1) as per http://stackoverflow.com/questions/14602062/java-string-split-removed-empty-values – Fast Engy Jul 16 '15 at 02:16
  • In this case you have to be careful with empty substring. That is ";;;".split(";") will produce empty array – Michal Pasinski May 09 '16 at 16:31
  • What if you would like to store the resulting items in a set rather than a list? – Moses Kirathe Mar 11 '18 at 16:07
  • @MosesKirathe: You should be able to do something like: `new HashSet(Arrays.asList(str.split(",")));`. – npinti Mar 12 '18 at 11:55
174

Well, you want to split, right?

String animals = "dog, cat, bear, elephant, giraffe";

String[] animalsArray = animals.split(",");

If you want to additionally get rid of whitespaces around items:

String[] animalsArray = animals.split("\\s*,\\s*");
Tomasz Nurkiewicz
  • 334,321
  • 69
  • 703
  • 674
44

You can split it and make an array then access like an array:

String names = "prappo,prince";
String[] namesList = names.split(",");

You can access it with its indexes

String name1 = namesList [0];
String name2 = namesList [1];

or using a loop

for(String name : namesList){
    System.out.println(name);
}
Laurel
  • 5,965
  • 14
  • 31
  • 57
Prappo
  • 892
  • 1
  • 9
  • 23
22

A small improvement: above solutions will not remove leading or trailing spaces in the actual String. It's better to call trim before calling split. Instead of this,

 String[] animalsArray = animals.split("\\s*,\\s*");

use

 String[] animalsArray = animals.trim().split("\\s*,\\s*");
user872858
  • 770
  • 7
  • 15
  • 1
    for ur second line, if we use trim() then we don't need space split like `("\\s*,\\s*")` just use `(",");` this will results same. – W I Z A R D Jan 10 '15 at 05:13
  • 5
    I'm not sure of that @WIZARD because trim remove only the left and right space of the string, but not the space in it. So the `trim(" string, with , space ")` will be `"string, with , space"`. – Thomas Leduc May 13 '15 at 08:08
  • @ThomasLeduc if string is like this `"dog, cat, bear, elephant, giraffe"` then no need of `trim()` and in ur case if use `trim()` then out put will be `"string,with,space"` not this `"string, with , space"` – W I Z A R D May 13 '15 at 08:34
  • `trim()` will remove all spaces not just left and right space of string – W I Z A R D May 13 '15 at 08:39
  • 6
    Do you test it ? because I've just wrote a program java and the string `" string, with , space ".trim()` return `"string, with , space"`. Like javadoc says : returns a copy of the string, with leading and trailing whitespace omitted. You are wrong and @user872858 is right. – Thomas Leduc May 13 '15 at 08:55
3

First you can split names like this

String animals = "dog, cat, bear, elephant,giraffe";

String animals_list[] = animals.split(",");

to Access your animals

String animal1 = animals_list[0];
String animal2 = animals_list[1];
String animal3 = animals_list[2];
String animal4 = animals_list[3];

And also you want to remove white spaces and comma around animal names

String animals_list[] = animals.split("\\s*,\\s*");
hash
  • 5,336
  • 7
  • 36
  • 59
3

For completeness, using the Guava library, you'd do: Splitter.on(",").split(“dog,cat,fox”)

Another example:

String animals = "dog,cat, bear,elephant , giraffe ,  zebra  ,walrus";
List<String> l = Lists.newArrayList(Splitter.on(",").trimResults().split(animals));
// -> [dog, cat, bear, elephant, giraffe, zebra, walrus]

Splitter.split() returns an Iterable, so if you need a List, wrap it in Lists.newArrayList() as above. Otherwise just go with the Iterable, for example:

for (String animal : Splitter.on(",").trimResults().split(animals)) {
    // ...
}

Note how trimResults() handles all your trimming needs without having to tweak regexes for corner cases, as with String.split().

If your project uses Guava already, this should be your preferred solution. See Splitter documentation in Guava User Guide or the javadocs for more configuration options.

Community
  • 1
  • 1
Jonik
  • 80,077
  • 70
  • 264
  • 372
2

Can try with this worked for me

 sg = sg.replaceAll(", $", "");

or else

if (sg.endsWith(",")) {
                    sg = sg.substring(0, sg.length() - 1);
                }
Tarit Ray
  • 944
  • 12
  • 24
2

in build.gradle add Guava

    compile group: 'com.google.guava', name: 'guava', version: '27.0-jre'

and then

    public static List<String> splitByComma(String str) {
    Iterable<String> split = Splitter.on(",")
            .omitEmptyStrings()
            .trimResults()
            .split(str);
    return Lists.newArrayList(split);
    }

    public static String joinWithComma(Set<String> words) {
        return Joiner.on(", ").skipNulls().join(words);
    }

enjoy :)

1

In Kotlin,

val stringArray = commasString.replace(", ", ",").split(",")

where stringArray is List<String> and commasString is String with commas and spaces

Kishan Solanki
  • 13,761
  • 4
  • 85
  • 82
1

Easy and Short solution:-

String str="test 1 ,test 2 , test 3";

List<String> elementList = Arrays.asList(str.replaceAll("\\s*,\\s*", ",").split(","));

Output=["test 1","test 2","test 3"]

It will working for all cases.

Thanks me later :-)

0

Remove all white spaces and create an fixed-size or immutable List (See asList API docs)

final String str = "dog, cat, bear, elephant, ..., giraffe";
List<String> list = Arrays.asList(str.replaceAll("\\s", "").split(","));
// result: [dog, cat, bear, elephant, ..., giraffe]

It is possible to also use replaceAll(\\s+", "") but maximum efficiency depends on the use case. (see @GurselKoca answer to Removing whitespace from strings in Java)

Community
  • 1
  • 1
sdc
  • 2,603
  • 1
  • 27
  • 40
0

You can use something like this:

String animals = "dog, cat, bear, elephant, giraffe";

List<String> animalList = Arrays.asList(animals.split(","));

Also, you'd include the libs:

import java.util.ArrayList;
import java.util.Arrays; 
import java.util.List;
Diego Cortes
  • 184
  • 4
0

Use this :

        List<String> splitString = (List<String>) Arrays.asList(jobtype.split(","));
Abhishek Sengupta
  • 2,938
  • 1
  • 28
  • 35
0

This is an easy way to split string by comma,

import java.util.*;

public class SeparatedByComma{
public static void main(String []args){
     String listOfStates = "Hasalak, Mahiyanganaya, Dambarawa, Colombo";
     List<String> stateList = Arrays.asList(listOfStates.split("\\,"));
     System.out.println(stateList);
 }
}
Sandun Susantha
  • 1,010
  • 1
  • 10
  • 11
0

"Old school" (JDK1.0) java.util Class StringTokenizer :

StringTokenizer(String str, String delim)

import java.util.*;

public class Tokenizer {
        public static void main(String[] args) {
                String str = "dog, cat, bear, elephant, ..., giraffe";
                StringTokenizer tokenizer = new StringTokenizer(str, ",");

                List<String> strings = new ArrayList<String>();

                while (tokenizer.hasMoreTokens()) {
                        // if need to trim spaces .trim() or use delim like ", "
                        String token = tokenizer.nextToken().trim();
                        strings.add(token);
                }
                // test output
                strings.forEach(System.out::println);
        }
}

NB: StringTokenizer is a legacy class that is retained for compatibility reasons although its use is discouraged in new code. It is recommended that anyone seeking this functionality use the split method of String or the java.util.regex package instead.

Example:

import java.util.regex.*;
...
// Recommended method<?>
Pattern commaPattern = Pattern.compile("\\s*,\\s*");
String[] words = commaPattern.split(str);
List<String> wordList = new ArrayList<String>(Arrays.asList(words));

// test output
wordList.forEach(System.out::println);
...
CamelTM
  • 1,225
  • 12
  • 17
-1

There is a function called replaceAll() that can remove all whitespaces by replacing them with whatever you want. As an example

String str="  15. 9 4;16.0 1"
String firstAndSecond[]=str.replaceAll("\\s","").split(";");
System.out.println("First:"+firstAndSecond[0]+", Second:"+firstAndSecond[1]);

will give you:

First:15.94, Second:16.01