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I want to set my outlier points in a boxplot to be semitransparent In here! they used "jitter" (similar idea, different approach)

my code

ggplot() + 
geom_boxplot(aes(x = Sistema, y=values, linetype = Sistema), 
             data=estacado, outlier.size=1, outlier.shape=2) + 
coord_flip() + 
labs(x="Sistema", y=expression(paste("RMSD ",(ring(A))))) +
opts(legend.position="none")

my data

>head(estacado)
    values   ind Sistema
1 0.310214 r24_a     R24
2 0.428232 r24_a     R24
3 0.460971 r24_a     R24
4 0.482923 r24_a     R24
5 0.492656 r24_a     R24
6 0.515591 r24_a     R24
> tail(estacado)
          values   ind Sistema
4999995 1.723030 g24_e     G24
4999996 1.718444 g24_e     G24
4999997 1.720745 g24_e     G24
4999998 1.737137 g24_e     G24
4999999 1.733106 g24_e     G24
5000000 1.738487 g24_e     G24

http://dl.dropbox.com/u/19202810/Rplot01.png http://dl.dropbox.com/u/19202810/Rplot01.png

In the mentioned link, they modified the function geom_boxplot; I was hoping something more easy like outlier.colour= alpha("black", 1/2) but that gives the error:

Error in do.call("layer", list(mapping = mapping, data = data, stat = stat,  : 
  could not find function "alpha"

Any help is appreciated.

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murpholinox
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1 Answers1

4

As of ggplot2 version 0.9.0, the alpha function was moved to the (then new) scales package. To use it, you need to include

library("scales")

in addition to 

library("ggplot2")

in your script.

Brian Diggs
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