Split decimal variable into integral and fraction parts

Question

I am trying to extract the integral and fractional parts from a decimal value (both parts should be integers):

decimal decimalValue = 12.34m;
int integral = (int) decimal.Truncate(decimalValue);
int fraction = (int) ((decimalValue - decimal.Truncate(decimalValue)) * 100);

(for my purpose, decimal variables will contain up to 2 decimal places)

Are there any better ways to achieve this?

A better approach may be not to use a decimal at all, but use an `int`/`long` representing "your value multipled by 100". — Rawling, May 22 '12 at 12:48
Beware of unusual values. The max value for a decimal is ~7.9e28. The max value for an int is ~2e9 (significantly smaller). Even long only goes to ~9e18. So if you know the value will always be >= 0 you can use a ulong which goes all the way to ~18e18, giving a bit more leeway. — Davio, May 22 '12 at 13:02
Following answer of a similar question may suits those needs for fractional part: http://stackoverflow.com/a/13038524/1178314 — Frédéric, Apr 28 '14 at 10:19

score 31 · Answer 1 · answered Apr 30 '15 at 09:35

31

       decimal fraction = (decimal)2.78;
        int iPart = (int)fraction;
        decimal dPart = fraction % 1.0m;

answered Apr 30 '15 at 09:35

Girish Sakhare

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Very good use of modulus operator on decimal. I did not expect this to work, but it does beautifully (and it's fast) :) – iCollect.it Ltd Sep 27 '17 at 09:14
I second @GoneCoding but the OP mentions "_both parts should be integers_". – Gerold Broser Jul 28 '19 at 14:34
@GeroldBroserreinstatesMonica Regarding the `dPart` variable, you can simply cast it as `integer`. – vchan Apr 02 '20 at 14:16
Not working if integer part is bigger that Int32.MaxValue – dimaaan May 19 '23 at 15:32

SOReader · Answer 2 · 2019-12-11T09:19:35.880

4

Try mathematical definition:

var fraction = (int)(100.0m * (decimalValue - Math.Floor(decimalValue)));

Although, it is not better performance-wise but at least it works for negative numbers.

edited Dec 11 '19 at 09:19

answered Jan 27 '14 at 14:13

SOReader

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Try to use this: var FileMinorPartClient = (int)(100.0m * (clientFileVersion - Math.Floor(clientFileVersion))); I get: "Operator '*' cannot be applied to operands of type 'decimal' and 'double'" (clientFileVersion is a double, a la 1.4) – B. Clay Shannon-B. Crow Raven Feb 19 '14 at 21:46
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@B.ClayShannon It says so because you cannot mix those two. Either change `100.0m` to `100.0` or make sure `decimalValue` is of `decimal` type – SOReader Feb 19 '14 at 22:31

score 3 · Answer 3 · edited Jun 08 '15 at 15:24

3

decimal fraction = doubleNumber - Math.Floor(doubleNumber)

or something like that.

edited Jun 08 '15 at 15:24

Stonz2

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answered Jun 08 '15 at 13:38

OMARY

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score 2 · Answer 4 · answered May 22 '12 at 12:42

2

How about:

int fraction = (int) ((decimalValue - integral) * 100);

answered May 22 '12 at 12:42

Barry Kaye

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score 1 · Answer 5 · edited May 23 '17 at 10:31

1

For taking out fraction you can use this solution:

Math.ceil(((f < 1.0) ? f : (f % Math.floor(f))) * 10000)

edited May 23 '17 at 10:31

Community

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answered Jun 24 '15 at 01:34

Aamol

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Split decimal variable into integral and fraction parts

5 Answers5