How to search the whole string for a specific word?

Question

I have this code which searches a string array and returns the result if the input string matches the 1st characters of a string:

for (int i = 0; i < countryCode.length; i++) {
            if (textlength <= countryCode[i].length()) {
                if (etsearch
                        .getText()
                        .toString()
                        .equalsIgnoreCase(
                                (String) countryCode[i].subSequence(0,
                                        textlength))) {
                    text_sort.add(countryCode[i]);
                    image_sort.add(flag[i]);
                    condition_sort.add(condition[i]);
                }
            }
        }

But i want to get those string also where the input string matches not only in the first characters but also any where in the string? How to do this?

you can easily achive this by java pattern matcher methods.have a look at example given in this link http://docs.oracle.com/javase/tutorial/essential/regex/matcher.html best of luck,if you found any query than ask me,Regars Aamirkhan I. — Aamirkhan, May 24 '12 at 16:25

score 27 · Accepted Answer · answered May 24 '12 at 15:33

27

You have three way to search if an string contain substring or not:

String string = "Test, I am Adam";
// Anywhere in string
b = string.indexOf("I am") > 0;         // true if contains 

// Anywhere in string
b = string.matches("(?i).*i am.*");     // true if contains but ignore case

// Anywhere in string
b = string.contains("AA")  ;             // true if contains but ignore case

answered May 24 '12 at 15:33

ρяσѕρєя K

132,198
53
198
213

1

More like "b = string.indexOf("I am") != -1;" – Shaun Apr 19 '17 at 07:14

score 8 · Answer 2 · answered Mar 31 '15 at 11:18

8

I have not enough 'reputation points' to reply in the comments, but there is an error in the accepted answer. indexOf() returns -1 when it cannot find the substring, so it should be:

    b = string.indexOf("I am") >= 0;

answered Mar 31 '15 at 11:18

Morris

593
7
7

I think you should use string.contains("I am") because it is faster and shorter. You can find further information here (https://stackoverflow.com/questions/498686/is-string-contains-faster-than-string-indexof#:~:text=IndexOf(string)%20has%20no%20options,search%20using%20FindNLSString%20from%20kernel32.). – maxmitz Jan 21 '22 at 13:26

score 3 · Answer 3 · answered May 24 '12 at 15:26

3

Check out the contains(CharSequence) method

answered May 24 '12 at 15:26

compuguru

1,035
1
10
20

score 0 · Answer 4 · answered May 24 '12 at 15:26

0

Try this-

etsearch.getText().toString().contains((String) countryCode[i]);

answered May 24 '12 at 15:26

MrEngineer13

38,642
13
74
93

score 0 · Answer 5 · answered May 24 '12 at 15:42

0

You could use contains. As in:

myString.contains("xxx");

See also: http://docs.oracle.com/javase/1.5.0/docs/api/java/lang/String.html, specifically the contains area.

answered May 24 '12 at 15:42

jsun1973

31
3

score 0 · Answer 6 · answered May 24 '12 at 15:43

Use the following:

public boolean contains (CharSequence cs)

Since: API Level 1

Determines if this String contains the sequence of characters in the CharSequence passed.

Parameters

cs the character sequence to search for.

Returns

true if the sequence of characters are contained in this string, otherwise false

score 0 · Answer 7 · answered Jul 29 '20 at 13:32

Actually, the default Arrayadapter class in android only seems to search from the beginning of whole words but by using the custom Arrayadapter class, you can search for parts of the arbitrary string. I have created the whole custom class and released the library. It is very easy to use. You can check the implementation and usage from here or by clicking on the link provided below.

https://github.com/mohitjha727/Advanced-Search-Filter

You can refer to this simple example- We have names " Mohit " and "Rohan" and if We put " M" only then Mohit shows up in search result, but when we put "oh" then both Mohit and Rohan show up as they have the common letter 'oh'.

Thank You.

How to search the whole string for a specific word?

7 Answers7

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