PHP Finding a domain name and domain extension from an array

Question

I have an array of data containing some domains with TLD extensions. I want to collect the domain name and TLD extension seperately.

E.g. From "hello.com" I want to collect "hello" as one variable, and then collect ".com" as another variable.

Another E.g. IMPORTANT, from "hello.co.uk" I want to collect "hello" as one variable, and then collect ".co.uk" as another variable.

My current code using pathinfo() will work correctly on "hello.com", but not "hello.co.uk". For "hello.co.uk" it will collect "hello.co" as one variable, and then collect ".uk" as another variable.

Here is the code I am using:

// Get a file into an array
$lines = file($_FILES['file']['tmp_name']);

// Loop through array
foreach ($lines as $line_num => $line) {
    echo $line;

    //Find TLD
    $tld = ".".pathinfo($line, PATHINFO_EXTENSION);
    echo $tld;

    //Find Domain
    $domain = pathinfo($line, PATHINFO_FILENAME);
    echo $domain;
    }

Hopefully I explained that well enough. I use stackoverflow a lot but couldn't find a specific example of this.

Thanks

[`list($domain, $tld) = explode('.', $line, 2);`](http://php.net/explode) — hakre, Jan 08 '13 at 03:15
What do you want to get for `subdomain.hello.co.uk`? The answers given so far will give domain = `subdomain`, extension = `hello.co.uk`. — Barmar, Jan 08 '13 at 03:28
@Barmar: For these cases there is http://data.iana.org/TLD/tlds-alpha-by-domain.txt - Which shows that OP is already looking for the subdomain on the most lefthand side. - for the other needs there is http://publicsuffix.org/ — hakre, Jan 08 '13 at 10:31

Taz · Accepted Answer · 2013-01-08T03:23:48.953

4

Instead of using functions intended for files, you could just use some simple string manipulation:

$domain = substr($line, 0, strpos($line, "."));
$tld = substr($line, strpos($line, "."), (strlen($line) - strlen($domain)));

edited Jan 08 '13 at 03:23

answered Jan 08 '13 at 03:18

Taz

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Edited my strpos to strstr because I doubted myself then realised I was right the first time... Lesson: never doubt one's self. – Taz Jan 08 '13 at 03:24

mynewaccount · Answer 2 · 2013-01-08T03:30:28.393

First method:

$domains = array("hello.co.uk", "hello.com");

foreach ($domains as $d) {

    $ext = strstr($d, '.'); // extension
    $index = strpos($d, '.');

    $arr = str_split($d, $index);

    $domain = $arr[0]; // domain name


    echo "domain: $domain, extension: $ext <br/>";

}

Second method: (Thanks to hakre)

$domains = array("hello.co.uk", "hello.com");

foreach ($domains as $d) {

    list($domain, $ext) = explode('.', $d, 2);
    echo "domain: $domain, extension: $ext <br/>";

}

score 1 · Answer 3 · answered Jun 20 '16 at 10:20

1

For work with two (co.uk) and three level TLDs (act.edu.au) you need library that using Public Suffix List (list of top level domains), I recomend to use TLDExtract.

answered Jun 20 '16 at 10:20

Oleksandr Fediashov

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1
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score 0 · Answer 4 · answered Jan 08 '13 at 04:03

Here's a function that's pretty flexible, and will work with everything from example.com to http://username:password@example.com/public_html/test.zip to ftp://username@example.com to http://www.reddit.com/r/aww/comments/165v9u/shes_allergic_couldnt_help_herself/

function splitDomain($url) { 
 $host = "";
 $url = parse_url($url);
 if(isset($url['host'])) { 
    $host = $url['host'];
 } else {
    $host = $url['path'];
 }
 $host = str_replace('www.','',$host);
 $tmp = explode('.', $host);
 $name = $tmp[0];
 $tld = $tmp[1];
return array('name'=>$name,'tld'=>$tld);
}

Good answer! :) +1 (PS. I'm the guy from here http://stackoverflow.com/questions/14087116/extract-address-from-string) — , Jan 08 '13 at 06:09

score 0 · Answer 5 · answered Jan 08 '13 at 07:53

0

There's no reliable way of doing this other than to use a large table of legal extensions.

A popular table is the one known as the Public Suffix List.

answered Jan 08 '13 at 07:53

Alnitak

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70
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PHP Finding a domain name and domain extension from an array

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