Is it possible to manually check LocateRegistry existing?

Question

I have found a safe way to get LocateRegistry (even if the registry does not already exist).

Registry registry = null;
try {
    registry = LocateRegistry.getRegistry(52365);
    registry.list();
    // This call will throw an exception if the registry does not already exist
}
catch (RemoteException e) { 
    registry = LocateRegistry.createRegistry(52365);
}

Is it possible to firstly check registry existence and use getRegistry or createRegistry in accordance with the result of the check?

No. If there is an error in the function you will need to catch it and react accordingly. — mercutio, Feb 20 '13 at 15:16
@mercutio I don't try to fully avoid exceptions. But I want avoid unnecessary calling of `getRegistry` when it doesn't exist. I've update the question. — Nelson Tatius, Feb 20 '13 at 15:26

score 2 · Accepted Answer · answered Feb 21 '13 at 01:22

Is it possible to firstly check registry existence and use getRegistry or createRegistry in accordance with the result of the check?

Certainly. Just try the createRegistry() first; catch the ExportException, which means it's already running, and do the getRegistry() unconditionally.

I want avoid unnecessary calling of getRegistry when it doesn't exist

That's not a valid concern. It is a virtually cost-free call. No network activity.

Is it possible to manually check LocateRegistry existing?

1 Answers1

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