Remote method invocation port in use

Question

I have created a Server, Client kind of program with RMI. But whenever I run my Server after starting the rmiregistry from command prompt, the port already in use error is thrown. Its only me who started the rmiregistry. I have checked it from netstat.

Server Code:

public class Server implements Runnable, Linker{


private static Server server = null;
    private static Linker l = null;
    private String name = null;
    public Server(){}

    public void setName(String name){
        this.name = name;
    }
    public String getName(){
        return name;               
    }  
    public void run(){
        while(!("Andy").equalsIgnoreCase(name)){

        }
    }
    public static void createStub(){
        try{
            server = new Server();
            l = (Linker) UnicastRemoteObject.exportObject(server, 1099);

            Registry registry = LocateRegistry.getRegistry();
            registry.bind("Link", l);
            System.out.println("Ready");
        }
        catch(Exception e){
            e.printStackTrace();
        }
    }                       
    public static void main(String[] args) {
        // TODO Auto-generated method stub
        createStub();
        Thread t = new Thread(server);

    }
}

Client Code:

public class Client implements Runnable{


private Scanner sc = new Scanner(System.in);
    private Linker linker = null;

    public void loadStub(){
        try{
            Registry registry = LocateRegistry.getRegistry(1099);
            linker = (Linker) registry.lookup("Link");

        }catch(Exception e){

        }
    }
    public void run(){
        String ip = null;
        while(sc.hasNext()&&!(ip = sc.nextLine()).equalsIgnoreCase(":q")){
            try {
                linker.setName(ip);
            } catch (RemoteException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
        }
    }


    public static void main(String...args){
        Client client = new Client();
        client.loadStub();
        Thread t = new Thread(client);
        t.start();
    }
}

Exception:

java.rmi.server.ExportException: Port already in use: 1099; nested exception is: 
java.net.BindException: Address already in use: JVM_Bind

Tai Le · Answer 1 · 2017-02-21T04:55:29.353

47

If you're using macOS, you can stop port following as:

First thing you need to find the PID_number: lsof -i :1099

And then kill that port: kill -9 PID_number

edited Feb 21 '17 at 04:55

answered Mar 12 '14 at 03:26

Tai Le

8,530
5
41
34

1

fwiw -9 is basically a 'force quit' – Shanimal Jan 16 '16 at 02:33
No. This will just kill the RMI Registry, which is needed. You have to find the underlying problem, not just shoot everything in sight. – user207421 Sep 16 '19 at 08:14

user207421 · Accepted Answer · 2018-11-04T04:31:55.103

7

The rmiregistry is using port 1099 in its process so you can't use it in yours. Either:

Start the registry in the same process, via LocateRegistry.createRegistry() (preferred).
Export your object on a different port.
Start the rmiregistry on a different port other than 1099.

edited Nov 04 '18 at 04:31

answered Dec 01 '11 at 08:15

user207421

305,947
44
307
483

That was the problem in my case. I figured it out and when I was about to post here, I found your reply. netstat -aon shows where it is listening. In this case its listening on all interfaces. – Andrews Dec 01 '11 at 16:51

score 7 · Answer 3 · answered Dec 01 '11 at 09:13

7

Use this Server code -

Registry registry = null;
try {
    registry = LocateRegistry.getRegistry(52365);//use any no. less than 55000
    registry.list();
    // This call will throw an exception if the registry does not already exist
}
catch (RemoteException e) { 
    registry = LocateRegistry.createRegistry(52365);
}

answered Dec 01 '11 at 09:13

anirudha mundada

596
1
6
14

2

Why less than 55000? The port also has to be > 1024 for most people. It would be much better to attempt the creation first, then if that fails do getRegistry)). Your way has a timing window problem. – user207421 Dec 06 '11 at 22:50
Is it possible to make without exceptions? http://stackoverflow.com/q/14982760/897090 – Nelson Tatius Feb 20 '13 at 14:55
@Lescott As I said in the question you quoted, no. – user207421 May 22 '13 at 18:22

score 0 · Answer 4 · answered Jul 05 '14 at 11:34

0

Use ps -aef |grep rmiregistry. find the pid which rmiregistry use. Kill the pid Den run the server again...!!!!

answered Jul 05 '14 at 11:34

user3796191

9
3

score 0 · Answer 5 · answered Dec 28 '17 at 10:30

0

Try this:

lsof -P | grep ':1099' | awk '{print $2}' | xargs kill -9

answered Dec 28 '17 at 10:30

Arif Acar

1,461
2
19
33

score 0 · Answer 6 · answered Dec 01 '11 at 06:22

0

Re-check if the port 1099 is not used by any other process or user or start the rmiregistry on some other port.

answered Dec 01 '11 at 06:22

Gaurav

1,549
2
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Remote method invocation port in use

6 Answers6

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