What is the inverse of date.toordinal() in python?

Question

In python, a dateobject can be converted in the proleptic Gregorian ordinal this way:

d=datetime.date(year=2010, month=3, day=1)
d.toordinal()

but what is the reverse operation?

Err.... [date.fromordinal](http://docs.python.org/2/library/datetime.html#datetime.date.fromordinal) ? — Jon Clements, May 14 '13 at 11:35

score 12 · Accepted Answer · answered May 14 '13 at 11:37

The opposite is date.fromordinal

classmethod date.fromordinal(ordinal)

Return the date corresponding to the proleptic Gregorian ordinal, where January 1 of year 1 has ordinal 1. ValueError is raised unless 1 <= ordinal <= date.max.toordinal(). For any date d, date.fromordinal(d.toordinal()) == d.

score 5 · Answer 2 · answered May 14 '13 at 11:36

It's date.fromordial() as Jon wrote in the comments.

or datetime.fromordinal()

You can read more about it in the date= documentation

and for datetime

From the docs:

classmethod date.fromordinal(ordinal)

Return the date corresponding to the proleptic Gregorian ordinal, where January 1 of year 1 has ordinal 1. ValueError is raised unless 1 <= ordinal <= date.max.toordinal().

For any date d, date.fromordinal(d.toordinal()) == d.

score 4 · Answer 3 · edited May 23 '17 at 12:25

4

I found the answer in this question.

>>> from datetime import datetime
>>> dt = datetime.fromordinal(733828)

edited May 23 '17 at 12:25

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answered May 14 '13 at 11:37

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What is the inverse of date.toordinal() in python?

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