Convert date to ordinal python?

Question

I want to convert 2010-03-01 to 733832

I just found this toordinal code

d=datetime.date(year=2010, month=3, day=1)
d.toordinal()

from this

But i want something more like

d=datetime.date('2010-03-01')
d.toordinal()

Thanks in advance

Answer 1

You'll need to use strptime on the date string, specifying the format, then you can call the toordinal method of the date object:

>>> from datetime import datetime as dt
>>> d = dt.strptime('2010-03-01', '%Y-%m-%d').date()
>>> d
datetime.date(2010, 3, 1)
>>> d.toordinal()
733832

The call to the date method in this case is redundant, and is only kept for making the object consistent as a date object instead of a datetime object.

If you're looking to handle more date string formats, Python's strftime directives is one good reference you want to check out.

Answer 2

like this:

datetime.strptime("2016-01-01", "%Y-%m-%d").toordinal()

Answer 3

You need to firstly convert the time string to datetime object using strptime(). Then call .toordinal() on the datetime object

>>> from datetime import datetime
>>> date = datetime.strptime('2010-03-01', '%Y-%M-%d')
>>> date.toordinal()
733773

It is even better to create a function to achieve this as:

def convert_date_to_ordinal(date):
    return datetime.strptime(date, '%Y-%M-%d').toordinal()

convert_date_to_ordinal('2010-03-01')
#returns: 733773