Getting domain extension from URL?

Question

I want to get the domain extension from the url. eg. .com, .net etc.

I have used this:

$extension = pathinfo($_SERVER['SERVER_NAME'], PATHINFO_EXTENSION);

I was just wondering if there was a better way using parse_url?

Better use $_SERVER['HTTP_HOST'] – Evert Jul 05 '13 at 11:15 — Evert, Jul 05 '13 at 11:15
How do you want to handle `.co.uk`? – PeeHaa Jul 05 '13 at 11:19 — PeeHaa, Jul 05 '13 at 11:19

score 10 · Answer 1 · edited May 23 '17 at 12:32

10

Use parse_url(). Something like:

$host = parse_url('http://www.google.co.uk/test.html');
preg_match('/(.*?)((\.co)?.[a-z]{2,4})$/i', $host['host'], $m);

$ext = isset($m[2]) ? $m[2]: '';

Edit: Fixed with regex from this answer. Extension like .co.uk are supported too.

edited May 23 '17 at 12:32

Community

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answered Jul 05 '13 at 11:21

Nadh

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This doesnt work with domains such as .co.uk – user1794021 Jul 05 '13 at 11:26
@user1794021, try the edited version. – Nadh Jul 05 '13 at 11:38
Returns `Undefined index: host` – Jimmy Obonyo Abor Jan 13 '16 at 23:11
`(.*?)((?:\.co|.com)?.[a-z]{2,4})$` if you want to support .com.xx extensions (such as .com.au). – keepthepeach Aug 11 '16 at 03:22

score -3 · Answer 2 · answered Jul 05 '13 at 11:16

You can easily split the requested URI like this:

function tld( $uri ) {
    $parts = explode('.', $uri);

    return (sizeof($parts) ? ('.' . end($parts)) : false;
}

So you can do this:

if(!tld('googlecom')) // does not contain an ending TLD

if(tld('google.com')) // this is a valid domain name; output: ".com"

Or you can just use:

echo $_SERVER['SERVER_NAME'];

So in my oppinion the most best example of usage is:

echo tld($_SERVER['SERVER_NAME']);

Getting domain extension from URL?

2 Answers2

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