How to get the value of row field (nested object) using jquery

Question

I am using Jquery grid to populate my data. In one of my grids, I am populating nested object using,

{
name : 'student.roll',
index : 'student.roll',
sortable: false,
width : 120

}

Now that, I need to parse the list of roll numbers for some manipulation.

var lista = jQuery("#student-grid").getDataIDs();
 for(i=0;i<lista.length;i++){
rowData=jQuery("#student-grid").getRowData(lista[i]);

 }

From this when i try to get rowData.student.roll, its trying to fetch an object called student but its a field name out there. How can I fetch the value of roll from jqgrid? Please help.

can you please put the HTML codes too . just to get you better... — Mayur Gupta, Oct 11 '13 at 12:49
@MayurGupta : Its just a div to which I bind my whole jqgrid as a table. Something like — Poppy, Oct 11 '13 at 12:51

score 1 · Accepted Answer · edited May 23 '17 at 12:10

1

You can use rowData["student.roll"] form. By the way I don't recommend you to use name property in colModel with special characters like .. You can use jsonmap or xmlmap mostly to read the data from the server which have having special characters in the name. For example name: 'student_roll', jsonmap: 'student.roll' will be better. In some more complex cases you can use jsonmap defined as functions (see the answer for more references to code examples).

edited May 23 '17 at 12:10

Community

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answered Oct 11 '13 at 12:51

Oleg

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Thanks! it worked perfectly :) i used rowData['student.roll']. But now I am changing my colModel.. – Poppy Oct 11 '13 at 13:04

score 1 · Answer 2 · answered Oct 11 '13 at 12:58

ok you can do it in this way...

<script type="text/javascript">
        $(document).ready(function () {
            $(".button").click(function (e) {

                var value= $(this).closest('tr').find("span[id*=student-grid]").text();

                alert(value);
                e.preventDefault();
            });
        });
    </script>

How to get the value of row field (nested object) using jquery

2 Answers2