In Typescript I can do this:
var xxx : some_type;
if (xxx)
foo();
else
bar();
Here xxx will be treated as a boolean, regardless of its type.
I would like to do the same thing in a function argument. I have this function:
function foo(b : boolean) { ... }
I want to be able to call foo(xxx)
and have xxx treated as a boolean, regardless of its type. But Typescript won't allow that.
I tried this:
foo(<boolean>xxx);
but that Typescript won't allow that either.
I can do this:
foo(xxx ? true : false);
But that seems a bit silly. Is there a better way to do it?