public class Test {
public static void main(String[] args) {
int i = 012;
System.out.println(i);
}
}
Why the output is : 10?
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Maroun
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Naveen Kocherla
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3printing an octal number – Kamlesh Arya Jan 29 '14 at 12:27
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2Don't forget to chose a right answer – diazazar Jan 29 '14 at 12:39
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2possible duplicate of [Integer with leading zeroes](http://stackoverflow.com/questions/565634/integer-with-leading-zeroes) – Raedwald Jan 30 '14 at 08:16
4 Answers
14
If a number starts with 0 it's an octal number with base 8. 012 is in decimal a 10
Constantin
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1@user2642221 You're welcome - if this answer solved your problem, please accept it as answer to your question (by clicking on the checkmark). – Constantin Jan 29 '14 at 12:38
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See the JLS:
An octal numeral consists of an ASCII digit 0 followed by one or more of the ASCII digits 0 through 7 interspersed with underscores, and can represent a positive, zero, or negative integer.
It's a good practice to write:
int i = 0_12;
It might be clearer now, i in decimal is 2*80 + 1*81 = 10.
Maroun
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Octal Number :
Any number start with 0 is considered as an octal number (012) i.e. base-8 number system
Simple octal number evaluation :
1*8^1 + 2*8^0 = 10
Kamlesh Arya
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012 is the octal value for 10 in decimal. So your telling java to print the integer at octal pos 012. Here: http://www.asciitable.com/ shows octal to decimal vaulue conversions.
javawocky
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