115

I have the following:

> date1
Timestamp('2014-01-23 00:00:00', tz=None)

> date2
datetime.date(2014, 3, 26)

and I read on this answer that I could use pandas.to_datetime() to convert from Timestamps to datetime objects, but it doesn't seem to work:

> pd.to_datetime(date1)   
Timestamp('2014-01-23 00:00:00', tz=None)

Why? How can I convert between these two formats?

Community
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Amelio Vazquez-Reina
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4 Answers4

158

You can use the to_pydatetime method to be more explicit:

In [11]: ts = pd.Timestamp('2014-01-23 00:00:00', tz=None)

In [12]: ts.to_pydatetime()
Out[12]: datetime.datetime(2014, 1, 23, 0, 0)

It's also available on a DatetimeIndex:

In [13]: rng = pd.date_range('1/10/2011', periods=3, freq='D')

In [14]: rng.to_pydatetime()
Out[14]:
array([datetime.datetime(2011, 1, 10, 0, 0),
       datetime.datetime(2011, 1, 11, 0, 0),
       datetime.datetime(2011, 1, 12, 0, 0)], dtype=object)
Andy Hayden
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28

Pandas Timestamp to datetime.datetime:

pd.Timestamp('2014-01-23 00:00:00', tz=None).to_pydatetime()

datetime.datetime to Timestamp

pd.Timestamp(datetime(2014, 1, 23))
10
>>> pd.Timestamp('2014-01-23 00:00:00', tz=None).to_datetime()
datetime.datetime(2014, 1, 23, 0, 0)
>>> pd.Timestamp(datetime.date(2014, 3, 26))
Timestamp('2014-03-26 00:00:00')
behzad.nouri
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-1

To answer the question of going from an existing python datetime to a pandas Timestamp do the following:

    import time, calendar, pandas as pd
    from datetime import datetime
    
    def to_posix_ts(d: datetime, utc:bool=True) -> float:
        tt=d.timetuple()
        return (calendar.timegm(tt) if utc else time.mktime(tt)) + round(d.microsecond/1000000, 0)
    
    def pd_timestamp_from_datetime(d: datetime) -> pd.Timestamp:
        return pd.to_datetime(to_posix_ts(d), unit='s')
    
    dt = pd_timestamp_from_datetime(datetime.now())
    print('({}) {}'.format(type(dt), dt))

Output:

(<class 'pandas._libs.tslibs.timestamps.Timestamp'>) 2020-09-05 23:38:55

I was hoping for a more elegant way to do this but the to_posix_ts is already in my standard tool chain so I'm moving on.

Timothy C. Quinn
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