verilog array of constant value

Question

How can I have an array of constant value or array of parameter? I want to use this array for select the part of an register, so It should be constant. Because I want to assign these parts to the input of a function that is generated in a for loop, I need an array to use index.

This is the part of my code which I have problem with, because in each iteration of i, I need a new encoderOut.

generate
  for ( i=0; i<row ; i=i+1) begin:hi
    for ( j=0; j<column ; j=j+1) begin:ji
      oneBitBlock #(choicesBit,selBit,funcBit,funcCount,(j+1)*row-1)U (rst,muxChoices[encoderOut-1:0],gene[pack*(i*row + j) +: encoderOut],gene[pack*(i*row + j)+encoderOut +: encoderOut],gene[pack*(i*row + j)+2*(encoderOut) +: funcBit],out[i*row + j]);
    end
  end
endgenerate

score 0 · Answer 1 · answered May 28 '14 at 10:23

There is no direct way to make an array of parameters, sadly. However, if your parameter values are limited, say to 32 bits, then you can concatenate those values and extract them using shifts and masks:

parameter TABLE = {32'd12,32'd45,32'd11}, // parameter values (value1,value2,value3...)
parameter TABLE_N   = 4, // number of entries in a table

Now, replace encoderOut with

((TABLE >> (32*(TABLE_N - i - 1 ))) & {32{1'b1}})

verilog array of constant value

1 Answers1