How to get device width and height?

Question

In Objective-C we can get device width and height by using following code :

CGRect sizeRect = [UIScreen mainScreen].applicationFrame
float width = sizeRect.size.width
float height = sizeRect.size.height

How can do this in with Swift ?

FYI - `applicationFrame` does not give the screen size. It gives the application size. It's better to use `bounds` instead of `applicationFrame` if you want the screen size. — rmaddy, Jun 06 '14 at 17:28
Yes, rmaddy you are right. I already made this changes in my app. Thanks for your response. — Divya Bhaloidiya, Nov 10 '14 at 07:38

score 179 · Accepted Answer · edited Nov 16 '17 at 05:16

179

I haven't tried but it should be..

var bounds = UIScreen.main.bounds
var width = bounds.size.width
var height = bounds.size.height

edited Nov 16 '17 at 05:16

Rbar

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answered Jun 06 '14 at 15:07

iPatel

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Its give OutOfScope Value.. When I am using your code Its give me typecasing error. – Divya Bhaloidiya Jun 06 '14 at 15:11
Oh, ,, yes its CGFloat not float .. check now – iPatel Jun 06 '14 at 15:12
1

Why not to use Swift auto type inference ? simply like: var bounds = UIScreen.mainScreen().bounds – Aks Dec 04 '14 at 11:05
2

@Aks It's safer and more readable to explicitly define the type. – AstroCB Jan 31 '15 at 00:22
how would you display the CGFloat values as an Int? – MoralCode Feb 02 '15 at 17:17
why is the result: (0.0, 0.0, 667.0, 667.0)? – S1U Apr 05 '16 at 08:54
FYI: `UIScreen.main.bounds.width` with latest sdk. – Satoshi Suzuki Apr 10 '17 at 08:05
If the device is in landscape the width and height will be opposite – aheze Dec 28 '20 at 00:54

Adam Smaka · Answer 2 · 2018-11-30T12:10:51.240

25

Swift 4.2

let screenBounds = UIScreen.main.bounds
let width = screenBounds.width
let height = screenBounds.height

edited Nov 30 '18 at 12:10

answered Jun 21 '16 at 07:52

Adam Smaka

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why am I getting: Use of unresolved identifier 'UIScreen'...? – Robbie Jan 15 '20 at 23:06
Probably need to import UIKit – Shawn Frank Jul 02 '21 at 20:16

score 20 · Answer 3 · edited Mar 02 '20 at 06:28

20

If you want to use it in your code. Here you go.

func iPhoneScreenSizes() {
    let bounds = UIScreen.main.bounds
    let height = bounds.size.height

    switch height {
    case 480.0:
        print("iPhone 3,4")
    case 568.0:
        print("iPhone 5")
    case 667.0:
        print("iPhone 6")
    case 736.0:
        print("iPhone 6+")
    case 812.0:
        print("iPhone X")
        print("iPhone XS")
        break
    case 896.0:
        print("iPhone XR")
        print("iPhone XS Max")
        break
    default:
        print("not an iPhone")

    }
}

edited Mar 02 '20 at 06:28

Bhadresh Kathiriya

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answered Mar 04 '16 at 17:34

bpolat

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20
26

2

@Jeff "not an iPhone" XD – mhdjazmati Oct 12 '19 at 10:16

score 18 · Answer 4 · answered Jun 06 '14 at 15:45

@Houssni 's answer is correct, but since we're talking Swift and this use case will come up often, one could consider extending CGRect similar to this:

extension CGRect {
    var wh: (w: CGFloat, h: CGFloat) {
        return (size.width, size.height)
    }
}

Then you can use it like:

let (width, height) = UIScreen.mainScreen().applicationFrame.wh

Hooray! :)

score 11 · Answer 5 · answered Sep 12 '16 at 18:59

(Swift 3) Keep in mind that most width and height values will be based on device's current orientation. If you want a consistent value that is not based on rotation and offers results as if you were in a portrait-up rotation, give fixedCoordinateSpace a try:

let screenSize = UIScreen.main.fixedCoordinateSpace.bounds

score 8 · Answer 6 · 2015-07-19T10:46:38.830

8

var sizeRect = UIScreen.mainScreen().applicationFrame
var width    = sizeRect.size.width
var height   = sizeRect.size.height

Exactly like this, tested it also.

edited Jul 19 '15 at 10:46

answered Jun 06 '14 at 15:08

4

Also without `;` LOL XD – Matteo Gobbi Jun 08 '14 at 22:38
1

Yeah like me and i'm really scared now! If i begin to write everything in `Swift` without semicolons and then again in `ObjectiveC` i will have probably `Ω(n)` compiling error LOL – Matteo Gobbi Jun 08 '14 at 22:46
2

@MatteoGobbi I consider using semicolons good practice... *use them.* – Cilan Oct 19 '14 at 00:29

score 6 · Answer 7 · answered Sep 29 '15 at 13:02

6

Since you're looking for the device screen size the simplest way is:

let screenSize = UIScreen.mainScreen().bounds.size
let width = screenSize.width
let height = screenSize.height

answered Sep 29 '15 at 13:02

ziligy

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score 5 · Answer 8 · answered Nov 20 '20 at 19:24

This works great for Xcode 12

func iPhoneScreenSizes() {
        let height = UIScreen.main.bounds.size.height
        switch height {
        case 480.0:
            print("iPhone 3,4")
        case 568.0:
            print("iPhone 5 | iPod touch(7th gen)")
        case 667.0:
            print("iPhone 6 | iPhone SE(2nd gen) | iPhone 8")
        case 736.0:
            print("iPhone 6+ | iPhone 8+")
        case 812.0:
            print("iPhone X | iPhone XS | iPhone 11 Pro")
        case 896.0:
            print("iPhone XR | iPhone XS Max | iPhone 11 | iPhone 11 Pro Max")
        default:
            print("not an iPhone")
        }
    }

score 4 · Answer 9 · answered Mar 14 '17 at 21:19

A UIScreen object defines the properties associated with a hardware-based display. iOS devices have a main screen and zero or more attached screens. Each screen object defines the bounds rectangle for the associated display and other interesting properties

Apple Doc URL :

https://developer.apple.com/reference/uikit/uiwindow/1621597-screen

To get Height/width of ur user's device with swift 3.0

let screenHeight = UIScreen.main.bounds.height
let screenWidth = UIScreen.main.bounds.width

score 4 · Answer 10 · answered Jan 20 '21 at 14:51

Here's an updated list of the sizes within a useable function:

func iScreenSizes() {
            let height = UIScreen.main.bounds.size.height
            print("Device height: \(height)")
            switch height {
            case 480.0:
                print("iPhone 3 | iPhone 4 | iPhone 4S")
            case 568.0:
                print("iPhone 5 | iPhone 5S | iPhone 5C | iPhone SE")
            case 667.0:
                print("iPhone 6 | iPhone 7 | iPhone 8 | iPhone SE(2nd gen)")
            case 736.0:
                print("iPhone 6+ | iPhone 7+ | iPhone 8+")
            case 780.0:
                print("iPhone 12 Mini")
            case 812.0:
                print("iPhone X | iPhone XS | iPhone 11 Pro")
            case 844.0:
                print("iPhone 12 | iPhone 12 Pro")
            case 896.0:
                print("iPhone XR | iPhone XS Max | iPhone 11 | iPhone 11 Pro Max")
            case 926.0:
                print("iPhone 12 Pro Max")
            case 1024.0:
                print("iPad 1st gen | iPad 2 | iPad 3rd gen | iPad mini | iPad 4th gen | iPad Air | iPad mini 2 | iPad mini 3 | iPad Air 2 | iPad mini 4 | iPad 5th gen | iPad 6th gen | iPad  mini 5")
            case 1112.0:
                print("iPad Pro 2nd gen 10.5'' | iPad Air 3")
            case 1194.0:
                print("iPad Pro 3rd gen 11.0'' | iPad Pro 4th gen 11.0''")
            case 1366.0:
                print("iPad Pro 1st gen 12.9'' | iPad 2nd gen 12.9'' | iPad 3rd gen 12.9'' | iPad Pro 4th gen 12.9''")
            default:
                print("not listed in function")
            }
        }

score 3 · Answer 11 · answered Nov 09 '16 at 08:58

3

While @Adam Smaka's answer was close, in Swift 3 it is the following:

let screenBounds = UIScreen.main.bounds
let width = screenBounds.width
let height = screenBounds.height

answered Nov 09 '16 at 08:58

Wyetro

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score 3 · Answer 12 · answered Nov 13 '19 at 16:13

 static func getDeviceType() -> String
    {
        var strDeviceType = ""
        if UIDevice().userInterfaceIdiom == .phone {
            switch UIScreen.main.nativeBounds.height {
            case 1136:
                strDeviceType = "iPhone 5 or 5S or 5C"
            case 1334:
                strDeviceType = "iPhone 6/6S/7/8"
            case 1920, 2208:
                strDeviceType = "iPhone 6+/6S+/7+/8+"
            case 2436:
                strDeviceType = "iPhone X"
            case 2688:
                strDeviceType = "iPhone Xs Max"
            case 1792:
                strDeviceType = "iPhone Xr"
            default:
                strDeviceType = "unknown"
            }
        }
        return strDeviceType
    }

score 1 · Answer 13 · answered Sep 27 '22 at 07:13

1

let bounds = UIScreen.main.bounds

answered Sep 27 '22 at 07:13

muhammad Zoraiz

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score 0 · Answer 14 · answered Apr 30 '18 at 13:58

0

In Swift 4 I had to use NSScreen.main?.deviceDescription

let deviceDescription = NSScreen.main?.deviceDescription          
let screenSize = deviceDescription![.size]
let screenHeight = (screenSize as! NSSize).height

answered Apr 30 '18 at 13:58

ohthepain

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score 0 · Answer 15 · answered Feb 12 '23 at 07:13

0

UIScreen.main.bounds will be deprecated in future version of iOS. Use view.window.windowScene.screen

 let height = view.window?.windowScene?.screen.bounds.height ?? 0
 let width = view.window?.windowScene?.screen.bounds.width ?? 0

answered Feb 12 '23 at 07:13

Taras

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How to get device width and height?

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